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vovangra [49]
2 years ago
15

Suppose you have a dipole that's free to move in any way (including rotate - imagine it floating in space). And there's an objec

t with charge Q a distance r away. That distance r would be much larger than d, the distance between the charges of the dipole, so we draw the dipole small.

Physics
1 answer:
Setler [38]2 years ago
5 0

Complete Question

The complete question shown on the first uploaded image

Answer:

a)

The force on Q due to dipole is Attractive

b)

The charge Q exerts attractive force on the dipole

c)

Yes from the above parts, force depends on the sign of charge

d)

   F = kQq[\frac{d^{2}+2rd}{r^{2}(d+r)^{2}} ]

e)

The magnitude o force decrease by a factor of 8.0 times

Explanation:

The explanation is shown on the second uploaded image

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In a racquetball game, your opponent repeatedly hits the same type of serve off the front wall and it lands in approximately the
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Answer:

b

Explanation:

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2 years ago
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Una persona de 80 kg de masa corre a una velocidad cuya magnitud es de 9m/s. Cual es la magnitud de la cantidad de movimiento? Q
natka813 [3]

Responder:

13,01 m / s

Explicación:

Paso uno:

datos dados

masa de la persona 1 m = 80 kg

velocidad de la persona 1 v = 9 m / s

masa de la persona 2 M = 55kg

velocidad de la persona 2 v =?

Segundo paso:

la expresión del impulso se da como

P = mv

para la primera persona, el impulso es

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P = 720N

Paso tres:

queremos que la segunda persona tenga el mismo impulso que la primera, por lo que la velocidad debe ser

720 = 55v

v = 720/55

v = 13,09

v = 13,01 m / s

Por lo tanto, la magnitud de la velocidad debe ser 13.01 m / s.

4 0
3 years ago
Which of the following graphs represents constant positive acceleration
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W, because as time is moving up at a consistent rate the speed is as well, creating the straight line.
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Which statement is true about acceleration?<br> who is an underated physicist?
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Two parallel-plate capacitors have the same plate area, but the plate gap in capacitor 1 is twice as big as capacitor 2. If capa
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Answer:

Capacitance of the second capacitor = 2C

Explanation:

\texttt{Capacitance, C}=\frac{\varepsilon_0A}{d}

Where A is the area, d is the gap between plates and ε₀ is the dielectric constant.

Let C₁ be the capacitance of first capacitor with area A₁ and gap between plates d₁.

We have    

              \texttt{Capacitance, C}_1=\frac{\varepsilon_0A_1}{d_1}=C

Similarly for capacitor 2

               \texttt{Capacitance, C}_2=\frac{\varepsilon_0A_2}{d_2}=\frac{\varepsilon_0A_1}{\frac{d_1}{2}}=2\times \frac{\varepsilon_0A_1}{d_1}=2C

Capacitance of the second capacitor = 2C

6 0
3 years ago
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