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vovangra [49]
3 years ago
15

Suppose you have a dipole that's free to move in any way (including rotate - imagine it floating in space). And there's an objec

t with charge Q a distance r away. That distance r would be much larger than d, the distance between the charges of the dipole, so we draw the dipole small.

Physics
1 answer:
Setler [38]3 years ago
5 0

Complete Question

The complete question shown on the first uploaded image

Answer:

a)

The force on Q due to dipole is Attractive

b)

The charge Q exerts attractive force on the dipole

c)

Yes from the above parts, force depends on the sign of charge

d)

   F = kQq[\frac{d^{2}+2rd}{r^{2}(d+r)^{2}} ]

e)

The magnitude o force decrease by a factor of 8.0 times

Explanation:

The explanation is shown on the second uploaded image

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What is the momentum of a 248 g rubber ball traveling at 30.0 m/s?
Vikentia [17]
<span>The answer is, 7.44 kg*m/s</span>
4 0
3 years ago
When you drop a 0.43 kg apple, Earth exerts
Archy [21]

Answer:

The acceleration of the earth is 7.05 * 10^-25 m/s²

Explanation:

<u>Step 1:</u> Data given

mass of the apple = 0.43 kg

acceleration = 9.8 m/s²

mass of earth = 5.98 * 10 ^24 kg

<u>Step 2:</u> Calculate the acceleration of the earth

Following the third law of Newton F = m*a

F(apple) = F(earth) = m(apple)*a(apple)

F(apple) = 0.43 kg * 9.8 m/s² = 4.214 N

a(earth) = F(apple/earth)/m(earth)

a(earth) = 4.214N /5.98 * 10 ^24 kg

a(earth) = 7.05 * 10^-25 m/s²

The acceleration of the earth is 7.05 * 10^-25 m/s²

4 0
3 years ago
You set out to design a car that uses the energy stored in a flywheel consisting of a uniform 80-kg cylinder of radius r that ha
Oliga [24]
E = 300km * 2000J/km = 600000J

The rotational energy is given by:
E = 0.5 * I * ω² 

I for a uniform cylinder is given by:
I  = 0.5 * m * r²

Resulting equation:
E = 0.25 * m * r² * ω²

Given values:
ω = 430 rev/s = 430 * 2π / s
E = 600000

Solve for r.
8 0
3 years ago
A hockey puck sliding on smooth ice at 4 m/s comes to a 1-m-high hill. Will it make it to the top of the hill?
solniwko [45]

Answer:

No  it will not make to the top of the hill  

Explanation:

From the question we are told that

   The velocity is  v  =  4 \ m/s

    The height of the hill is  h  = 1 \  m

Generally from the law of energy conservation we have that

   The kinetic energy of the pluck at the level position =  The potential energy of the pluck at the maximum height the  pluck can get  to  

So

       \frac{1}{2}  * m * v^2 =  m *  g *  h_{max}

=>    \frac{1}{2}   * v^2 =    g *  h_{max}

=>     h_{max} =   \frac{0.5 * v^2}{g}

=>     h_{max} =  0.8163 \  m

Given that the maximum height which the pluck can get to at this speed given in the question is less than the height of the hill then conclusion will be that the pluck will not make it to the top of the hill

     

3 0
3 years ago
A client with a head injury is being monitored for increased intracranial pressure (ICP). The client's blood pressure is 90/60 m
artcher [175]

Answer:

CPP=52mm \ Hg

Explanation:

<em>Cerebral Perfusion Pressure</em><em> </em>is obtained by subtracting <em>IntraCranial Pressure</em>(ICP) from the <em>Mean Arterial Pressure</em>(MAP). Adequate cerebral perfusion requires a minimum goal of 70mm \ Hg. MAP is obtained using the formula:-

MAP=\frac{(diastolic \ blood \ pressure\times2)+\ systolic \ blood \ pressure)}{3}\\\\MAP=\frac{2\times60+90}{3}\\\\MAP=70mm \ Hg\\CPP=MAP-ICP\\CPP=70-18\\CPP=52mm \ Hg

5 0
3 years ago
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