Ask question

Ask question

All categories

2 years ago

11

If the road becomes wet or crowded, you should ____. slow down and increase your following distance All choices are incorrect. m

aintain your speed and following distance speed up and decrease your following distance Submit answer

1 answer:

Vaselesa [24]2 years ago

7 0

Answer:

The first one.

You might be interested in

5. Two charged particles are separated by a distance of 12 meters. The Coulomb force between them is 20 N. What will the Coulomb

Leni [432]

Answer:

A) 80 N

Explanation:

The closer the particles get, the stronger the Coulomb force, which elongates choices C and D. The Coulomb force is inversely proportional to the distance squared. If the distance is cut in half, the force is multiplied by the reciprocal of (1/2)^2, which is 4. Multiplying it out, 20 times 4 is 80 N.

8 0

2 years ago

A train travels 8.81 m/s in a -51.0° direction.

Amiraneli [1.4K]

The displacement of the train after 2.23 seconds is 25.4 m.

<h3>Resultant velocity of the train</h3>

The resultant velocity of the train is calculated as follows;

R² = vi² + vf² - 2vivf cos(θ)

where;

θ is the angle between the velocity = (90 - 51) + 37 = 76⁰

R² = 8.81² + 9.66² - 2(8.81 x 9.66) cos(76)

R² = 129.75

R = √129.75

R = 11.39 m/s

<h3>Displacement of the train</h3>

Δx = vt

Δx = 11.39 m/s x 2.23 s

Δx = 25.4 m

Thus, the displacement of the train after 2.23 seconds is 25.4 m.

Learn more about displacement here: brainly.com/question/2109763

#SPJ1

8 0

1 year ago

A point charge q1 = 1.0 µC is at the origin and a point charge q2 = 6.0 µC is on the x axis at x = 1 m.

iris [78.8K]

To solve this problem we will apply the concepts related to the Electrostatic Force given by Coulomb's law. This force can be mathematically described as

$F = \frac{kq_1q_2}{d^2}$

Here

k = Coulomb's Constant

$q_{1,2} =$ Charge of each object

d = Distance

Our values are given as,

$q_1 = 1 \mu C$

$q_2 = 6 \mu C$

d = 1 m

$k = 9*10^9 Nm^2/C^2$

a) The electric force on charge $q_2$ is

$F_{12} = \frac{ (9*10^9 Nm^2/C^2)(1*10^{-6} C)(6*10^{-6} C)}{(1 m)^2}$

$F_{12} = 54 mN$

Force is positive i.e. repulsive

b) As the force exerted on $q_2$ will be equal to that act on $q_1$ ,

$F_{21} = F_{12}$

$F_{21} = 54 mN$

Force is positive i.e. repulsive

c) If $q_2 = -6 \mu C$ , a negative sign will be introduced into the expression above i.e.

$F_{12} = \frac{(9*10^9 Nm^2/C^2)(1*10^{-6} C)(-6*10^{-6} C)}{(1 m)^{2}}$

$F_{12} = F_{21} = -54 mN$

Force is negative i.e. attractive

6 0

3 years ago

A 600 N force acts on an object with a mass of 50 kg. What is the resulting acceleration of the object?

DochEvi [55]

Answer:

<h3>The answer is 12 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

$a = \frac{f}{m} \\$

f is the force

m is the mass

From the question we have

$a = \frac{600}{50} = \frac{60}{5} \\$

We have the final answer as

<h3>12 m/s²</h3>

Hope this helps you

4 0

2 years ago

A family car has a mass of 1400 kg. In an accident it hits a wall and goes from a speed of 27 m/s to a standstill in 1. 5 second

madreJ [45]

The force involved is = 25200 Newton

Given the values in the questions,

Mass = 1400 kg

Speed or velocity of the car = 27 m/s

Time is given = 1.5 seconds

According to the formula of force,

⇒ Force = Mass x Acceleration

⇒ Force = 1400 x Acceleration ----- equation 1

Now to calculate the value of acceleration we will use,

⇒ Acceleration = (Velocity or Speed) / Time

⇒ Acceleration = 27 / 1.5

⇒ Acceleration = 18 m/ $s^{2}$

Putting the value of acceleration in equation 1,

⇒ Force = 1400 x 18

⇒ Force = 25200 Newton

Therefore, the force involved is = 25200 Newton

To learn more about Force,

brainly.com/question/13191643

#SPJ4

8 0

1 year ago