An ionization suppressor is an alkali metal capable of preventing ionization, which can be used in atomic spectroscopy to determine matter composition.
<h3>What is ionization?</h3>
Ionization refers to the phenomena capable of converting neutral atoms/molecules to electrically charged atoms/ions.
Ionization is a process by which radiation (e.g., alpha, beta, gamma rays) can pass energy to inert matter.
Some examples of ionization suppressors include salts of alkali metals (for example, potassium), which can be used in atomic spectroscopy to determine matter composition.
Learn more about ionization here:
brainly.com/question/1445179
The total kinetic energy of the gas sample is 3.3 KJ
<h3>What is kinetic energy? </h3>
This is the energy possessed by an object in motion. Mathematically, it can be expressed as:
KE = ½mv²
Where
- KE is the kinetic energy
- m is the mass
- v is the velocity
<h3>How to determine the mass of the fluorine gas</h3>
- Molar mass of fluorine gas = 38 g/mol
- Mole of fluorine gas = 1 mole
- Mass of fluorine gas = ?
Mass = mole × molar mass
Mass of fluorine gas = 1 × 38
Mass of fluorine gas = 38 g
<h3>How to determine the KE of the gas sample</h3>
- Mass (m) = 38 g = 38 / 1000 = 0.038 Kg
- Velocity (v) = 415 m/s
- Kinetic energy (KE) =?
KE = ½mv²
KE = ½ × 0.038 × 415²
KE = 3272.275 J
Divide by 1000 to express in kilojoule
KE = 3272.275 / 1000
KE = 3.3 KJ
Learn more about energy:
brainly.com/question/10703928
#SPJ1
Answer:
1528.3L
Explanation:
To solve this problem we should know this formula:
V₁ / T₁ = V₂ / T₂
We must convert the values of T° to Absolute T° (T° in K)
21°C + 273 = 294K
70°C + 273 = 343K
Now we can replace the data
1310L / 294K = V₂ / 343K
V₂ = (1310L / 294K) . 343K → 1528.3L
If the pressure keeps on constant, volume is modified directly proportional to absolute temperature. As T° has increased, the volume increased too
<span>The ionic charge of Calcium (Ca) in calcium carbonate (CaCO3) is 2+. CaCO3 has a neutral ionic charge sin CO3 has a 2- charge.</span>
Answer:
8.194 Mev per nucleon
Explanation:
Mass of Barium = 135.905 amu
number of proton = 56, number of neutron = 80
Md = (Mp + Mn) - Mb Mp is the mass of proton, Mn is the mass of neutron, Mb is the mass of barium and Md is the mass defect
Mn = 1.00867 amu Mp = 1.00728 amu
Md = ( 56 ( 1.00728) + 80 ( 1.00867) = 137.1013 - 135.905 =1.1963 amu
Md = 1.1963 × 1 ÷ ( 6.02214 × 10 ²⁶ amu ) = 1.9865 × 10 ⁻²⁷ kg
Energy = mc² = 1.9865 × 10 ⁻²⁷ kg × (2.99792 × 10 ⁸ m/s)²
E= 1.78537 × 10⁻¹⁰ J
to convert to Mev
1.78537 × 10⁻¹⁰ × 6241457006000 = 1114.33 Mev
binding energy per nucleon = 1114.33 / 136 =8.194 Mev per nucleon
