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4 years ago

Help please! Test tomorrow!

Physics

1 answer:

Ede4ka [16]4 years ago

7 0

NONE of the choices is a true statement.

This is a very poor question. If you see anything like it on the test, you should not even try to answer it. Later, if it's marked wrong and you lose credit for it, you can protest it, and take this answer to school for support.

Whoever wrote this question seems to be largely unaware of the fact that the stars <u><em>move</em></u> across the night sky, for the same reason and at the same rate that the sun does the same thing all day.

-- Simply seeing a star near the horizon at some time of night tells you nothing about its visibility throughout the year.

-- MOST of the stars that you see near the Eastern horizon WILL BE high in the sky in a few hours.

-- MOST of the stars that you see near the Western horizon WERE high in the sky a few hours ago.

-- ALL of the stars that you see high overhead either WERE near the horizon a few hours ago, or WILL BE near the horizon in a few hours.

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suppose your bathroom scale reads your mass is 55 kg, with a 1% uncertainty. what is the uncertainty in your mass in kilograms?

skelet666 [1.2K]

Answer:

± .55 kg

Explanation:

55 * 1% = .55 kg

± .55 kg

8 0

2 years ago

As the temperature decreases, the atoms lose energy. The atoms begin to move slower. They are held together by attractive forces

Harlamova29_29 [7]

Melting ,vaporization and sublimation

5 0

3 years ago

Read 2 more answers

A proton moves north with a speed of 3 x 10^6 m/s. A 5 Tesla magnetic field is directed west. Determine the magnitude and direct

Andreyy89

The magnitude of magnitude force on the proton is 2.4 x 10⁻¹² N.

<h3>Magnitude of magnetic force on the proton</h3>

The magnitude of magnitude force on the proton is calculated as follows;

F = qvB sinθ

where;

q is the charge of the proton
v is the speed of the proton
B is the magnitude of the magnetic filed
θ is the angle between the field and speed

Substitute the given parameters and solve for the magnetic force.

F = (1.6 x 10⁻¹⁹) x (3 x 10⁶) x (5) X(sin90)

F = 2.4 x 10⁻¹² N

Thus, the magnitude of magnitude force on the proton is 2.4 x 10⁻¹² N.

Learn more about magnetic force here: brainly.com/question/13277365

7 0

3 years ago

A man pushed on the side ..

TiliK225 [7]

Answer:

B.will increase the maximum static friction between the box and the floor

Explanation:

Because static friction is the force that keeps an object at rest

7 0

3 years ago

A moon orbits a planet every 42 hours with a mean orbital radius of .002819 AU. The mass of the moon is 8.932 x 1022 kg. Using N

Pepsi [2]

Answer:

The mass of the planet is $1.9407\times10^{27}\ kg$

Explanation:

Given that,

Time period = 42 hours = 151200 sec

Orbital radius = 0.002819 AU = 421716397.5 m

Mass of moon $m=8.932\times10^{22}\ kg$

We need to calculate the mass of the planet

Using Kepler’s third law

$T^2\propto a^3$

$T^2=\dfrac{4\pi^2}{G(M+m)}\times a^3$

Where, a = orbital radius

T = time period

G = gravitational constant

M = mass of moon

m = mass of planet

Put the value into the formula

$(151200)^2=\dfrac{4\pi^2}{6.673\times10^{-11}(8.932\times10^{22}+m)}\times(421716397.5)^3$

$(8.932\times10^{22}+m)=\dfrac{4\pi^2}{6.673\times10^{-11}}\times\dfrac{(421716397.5)^3}{(151200)^2}$

$(8.932\times10^{22}+m)=1.94087\times10^{27}$

$m=1.94087\times10^{27}-8.932\times10^{22}$

$m=1.9407\times10^{27}\ kg$

Hence, The mass of the planet is $1.9407\times10^{27}\ kg$

8 0

4 years ago