<span>At room temperature and atmospheric pressure, nothing happens when the two gasses are mixed. However, at high temperature and pressure (450C, 200atm), in the presence of an iron oxide catalyst, the production of ammonia is thermodynamically advantageous.</span>
Answer: The mole ratio of oxygen to pentane for the combustion of pentane is 8 : 1.
Explanation: The given reaction is a type of combustion reaction.
Combustion reaction is a reaction in which a hydrocarbon reacts with oxygen gas to produce water and carbon dioxide gas.
For the reaction of pentane with oxygen, the balanced equation would be:

In the reaction, 1 mole of
reacts with 8 moles of
gas.
Thus giving us the mole ratio as
Oxygen : Pentane = 8 : 1
Answer:
Concentration of original solution = 1.66
Explanation:
We know that

We have given concentration of NaOH = 0.1678
Volume of NaOH = 19.88 mL = 0.01988 L
So moles of NaOH = volume x concentration of NaOH
= 
Moles of
in 10 mL of diluted solution = 1/2 x moles of NaOH
=
x 0.00333 = 0.00166 mol
Moles of
in 25 mL of original solution
= moles of H2SO4 in 250 mL of diluted solution
=
x 0.00166 = 0.0415 mol
Concentration of original solution = 
= 
Let the water evaporate and you'll be left with the sugar, or boil the water and collect the steam. the sugar will be left in the container you boiled the water in and you'll still have the water from the steam.
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