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3 years ago

Can you please solve the following equation?

Mathematics

1 answer:

AlladinOne [14]3 years ago

7 0

Answer:

x=3.903

Step-by-step explanation:

$2^{x-3}.5^{x-1}=200\\2^x.2^{-3}.5^x.5^{-1}=200\\\frac{2^x}{2^3}.\frac{5^x}{5^1}=200\\\frac{2^x.5^x}{2^3.5}=200\\\frac{(2.5)^x}{8.5}=200\\10^x=200 \times 40\\10^x=8000\\log 10^x=log8000\\x=\frac {log8000}{log10}=log8000=log 8\times log1000=log 8+log 1000=log2^3+log10^3=3log2+3log10=3log2+3 \approx0.903+3 \approx3.903$

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Step-by-step explanation:

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3 years ago

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3 years ago

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