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3 years ago

What is the area of this figure?

Mathematics

1 answer:

nignag [31]3 years ago

5 0

Answer:

44 square units

Step-by-step explanation:

The area of the 2 upper triangles is:

2 * ((1/2) * b * h) = 2 * ( (1/2) * 4 * 3) = 2 * 6 = 12

The area of the rectangle in the middle of the figure is:

b * h = 8 * 3 = 24

The area of the lower triangle is:

1/2 * b * h = 1/2 * 2 * 8 = 8

The area of the composite figure is:

Area of the 2 upper triangles + area of the rectangle + the area of the lower triangle = 12 + 24 + 8 = 44 square units (area is always given in square units)

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If function f is a cubic polynomial which statement most accurately describes the function over the interview (0,1)

inysia [295]

Answer:

Option (B)

Step-by-step explanation:

From the given table,

With the increase in the values of x (from x = -2 to x = 2), values of the function is decreasing from x =2 to x = 4.

Interval (0, 1) lies in the domain of the function in which the y-values of the function are,

At x = 0,

f(0) = -6

At x = 1,

f(1) = 0

Therefore, values of the given function are increasing in the interval of (0, 1).

Option (B) will be the correct option.

7 0

3 years ago

Helppppppppppp!!!!!

Delvig [45]

Answer:

$n ^{2} + 7n + 1 \\ where \: the \: value \: of \: n = - 3 \\ n ^{2} + 7n + 1 \\ = - 3^{2} + 7( - 3) + 1 \\ = - 9 - 21 + 1 \\ = - 29$

4 0

2 years ago

Read 2 more answers

If you are a dog lover, having your dog with you may reduce your stress level. Does having a friend with you reduce stress? To e

Pepsi [2]

The outlier of a dataset is a data element that is relatively far from the remaining data elements

99 is an outlier of pet group
See attachment for the parallel box plots

(a) Prove that 99 is an outlier for Pet

We have:

Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99

$n = 15$

The quartiles positions are:

$Q_1 = \frac{n + 1}{4}$

$Q_1 = \frac{15 + 1}{4}$

$Q_1 = \frac{16}{4}$

$Q_1 = 4th$

$Q_3 = Q_1 \times 3$

$Q_3 = 4th \times 3$

$Q_3 = 12th$

So, we have:

$Q_1 = 4th$

$Q_3 = 12th$

From the pet group:

The data elements at the 4th and 12th positions are 68 and 79

So, we have:

$Q_1 = 68$

$Q_3= 79$

The lower and upper limits of the outlier are:

$L = Q_1 - 1.5 \times (Q_3 - Q_1)$

$U = Q_3 + 1.5 \times (Q_3 - Q_1)$

So, we have:

$L = 68 - 1.5 \times (79 - 68)$

$L = 51.5$

$U = 79+ 1.5 \times (79 - 68)$

$U = 95.5$

This means that data below 51.5 or above 95.5 are outliers.

Hence, 99 is an outlier because 99 is greater than 95.5

(b) The parallel box plot

The three groups are:

Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99

Erlento: 88 80 80 81 92 87 88 81 82 80 87 92 87 80 82

Alone: 62 70 73 75 77 80 84 84 84 87 87 87 90 91 99

See attachment for the parallel box plots

Read more about box plots and outliers at:

brainly.com/question/14940764

5 0

3 years ago

Help me with math please, really urgent!

Alenkasestr [34]

X2 is on the right side, X1 is on the left side so -14 would be X1 and 2 would be x2

so it would be the first answer

7 0

3 years ago

BRAINLIESTTT ASAP!! PLEASE HELP ME :)

4vir4ik [10]

No they are not equivalent.

When you multiply a number raised to an exponent to an identical number with an exponent you actually add the exponents together, not multiply them.

So x^3 * x^3 * x^3 would simplify to x^9

The second equation has a single value raised to exponents multiplied by each other so x^3*3*3 would simplify to x^27

X^9 is not the same as x^27

6 0

2 years ago