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puteri [66]
3 years ago
12

Match the labels to the

Chemistry
2 answers:
Ipatiy [6.2K]3 years ago
7 0
For the first blank, that is the endoplasmic reticulum
For the second, it is lysosome
For the third blank, it is the cell membrane
For the fourth, sorry I don’t know this one
For the fifth, that is the vacuole
For the sixth, that is mitochondrion
For the seventh, that is Golgi body
And lastly the eighth, it is the nucleus
Sorry I did not know what the fourth was but everything else is good.
igomit [66]3 years ago
5 0

Answer: For the first blank, that is the endoplasmic reticulum

For the second, it is lysosome

For the third blank, it is the cell membrane

For the fourth, it is the ribosomes

For the fifth, that is the vacuole

For the sixth, that is mitochondrion

For the seventh, that is Golgi body

And lastly the eighth, it is the nucleus

It goes in a circle from top left to top right

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Jordan needs to repeat the experiment but his teacher says that he needs to improve his design in his second experiment what sho
Margarita [4]
Just add more detail in the second experiment explain every little thing.
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3 years ago
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If a 1.00 mL sample of the reaction mixture for the equilibrium constant experiment required 32.40 mL of 0.258 M NaOH to titrate
andrey2020 [161]

Answer:

The concentration of acetic acid is 8.36 M

Explanation:

Step 1: Data given

Volume of acetic acid = 1.00 mL = 0.001 L

Volume of NaOH = 32.40 mL = 0.03240 L

Molarity of NaOH = 0.258 M

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate the concentration of the acetic acid

b*Ca*Va = a*Cb*Vb

⇒with b = the coefficient of NaOH = 1

⇒with Ca = the concentration of CH3COOH = TO BE DETERMINED

⇒with Va = the volume of CH3COOH = 1.00 mL = 0.001L

⇒with a = the coefficient of CH3COOH = 1

⇒with Cb = the concentration of NaOH = 0.258 M

⇒with Vb = the volume of NaOH = 32.40 mL = 0.03240 L

Ca * 0.001 L = 0.258 * 0.03240

Ca = 8.36 M

The concentration of acetic acid is 8.36 M

6 0
3 years ago
The [H+] of a solution can be determined from the pH using the equation: [H+] = 10 - pH ... Where: [H+] = hydrogen ion concentra
padilas [110]

Answer:

pH = -log₁₀ [H⁺]

Explanation:

pH is a value in chemistry used in to measure solution trying to determine each quality, purity, risks for health of some products, etc.

As you write in the question, [H⁺] = 10^(-pH)

Using logarithm law (log (m^(p) = p log(m):

log₁₀ [H⁺] = -pH

And

<h3>pH = -log₁₀ [H⁺]</h3>
8 0
3 years ago
Calculate the molarity of hydroxide ion in an aqueous solution that has a poh of 5.00
Simora [160]

Answer:

1.00 x 10^-5 M

Explanation:

pOH=-log[OH^-]

so

[OH^-]=10^(-pOH)

=10^-5

=1.00 x 10^-5 M

4 0
3 years ago
How is the pH of an acidic substance raised?
ch4aika [34]

Explanation:

An acid is a substance that produces excess hydroxonium ions in solution.

An acid based on the pH scale is a substance that has a low pH. Acid lies within a range of 1-7 on the pH scale.

  • A pH of 7 is for neutral compounds like water.
  • A pH greater that 7 is for basic compounds.
  • In order to raise the pH, we are driving at a substance becoming more neutral or basic.

This can be achieved by adding more base to the solution of the substance. When we add more base, hydroxyl ions will neutralize the excess hydroxonium ions and drag the pH towards that of neutrality.

Addition of more base can eventually make the substance basic.

learn more:

Phosphoric acid brainly.com/question/11062486

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