Answer: 351
Explanation: From °C to kelvin we do
K=273+°C
From Kelvin to °C we do
°C=K-273 or -273+ K
The amount of Al2O3 in moles= 1.11 moles while in grams = 113.22 grams
<em><u>calculation</u></em>
2 Al + Fe2O3 → 2Fe + Al2O3
step 1: find the moles of Al by use of <u><em>moles= mass/molar mass </em></u>formula
= 60.0/27= 2.22 moles
Step 2: use the mole ratio to determine the moles of Al2O3.
The mole ratio of Al : Al2O3 is 2: 1 therefore the moles of Al2O3= 2.22/2=1.11 moles
Step 3: finds the mass of Al2O3 by us of <u><em>mass= moles x molar mass</em></u><em> </em>formula.
The molar mass of Al2O3 = (2x27) +( 16 x3) = 102 g/mol
mass is therefore= 102 g/mol x 1.11= 113.22 grams
Explanation:
I hope this helps Chemistry is so hard and I hate it
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☃️ Chemical formulae ➝ ![\sf{I_2}](https://tex.z-dn.net/?f=%5Csf%7BI_2%7D)
How to find?
For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.
![\boxed{ \sf{No. \: of \: moles = \frac{Given \: weight}{Molecular \: weight} }}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%20%5Csf%7BNo.%20%5C%3A%20of%20%5C%3A%20moles%20%3D%20%20%5Cfrac%7BGiven%20%5C%3A%20weight%7D%7BMolecular%20%5C%3A%20weight%7D%20%7D%7D)
Solution:
❍ Molecular weight of ![\sf{I_2}](https://tex.z-dn.net/?f=%5Csf%7BI_2%7D)
= 2 × 126.90
= 253.80
= 254 (approx.)
❍ Given weight: 12.7
Then, no. of moles,
⇛ No. of moles = 12.7 / 254
⇛ No. of moles = 0.05 moles
⚘ No. of moles of Iodine molecule in the given weight = <u>0.05</u><u> </u><u>moles </u>
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