<u>Answer:</u> The equilibrium constant for the given reaction is 4.224
<u>Explanation:</u>
We are given:
Equilibrium concentration of water = 0.250 M
Equilibrium concentration of hydrogen gas = 0.330 M
Equilibrium concentration of oxygen gas = 0.800 M
For the given chemical reaction:
The expression of 
for above reaction follows:
![K_{eq}=\frac{[H_2][O_2]}{[H_2O]^2}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BH_2%5D%5BO_2%5D%7D%7B%5BH_2O%5D%5E2%7D)
Putting values in above expression, we get:
Hence, the equilibrium constant for the given reaction is 4.224
Answer:
a) p = 1.10 * 10⁻²⁷ kg·m/s
b) p = 9.46 * 10⁻²⁴ kg·m/s
c) p = 3.31 * 10⁻³⁶ kg·m/s
Explanation:
To solve this problem we use the <em>de Broglie's equation, </em>which describes the wavelenght of a photon with its momentum:
λ=h/p
Where λ is the wavelength, h is Planck's constant (6.626 * 10⁻³⁴ J·s), and p is the linear momentum of the photon.
Rearrange the equation in order to solve for p:
p=h/λ
And now we proceed to calculate, <u>keeping in mind the SI units</u>:
a) 600 nm= 600 * 10⁻⁹ m
p=(6.626 * 10⁻³⁴ J·s) / (600*10⁻⁹m) = 1.10 * 10⁻²⁷ kg·m/s
b) 70 pm= 70 * 10⁻¹² m
p=(6.626 * 10⁻³⁴ J·s) / (70*10⁻¹²m) = 9.46 * 10⁻²⁴ kg·m/s
c) 200 m
p=(6.626 * 10⁻³⁴ J·s) / (200m) = 3.31 * 10⁻³⁶ kg·m/s
Answer:
Yes they are found in same period
Answer:
A.), as it will decrease.
Answer:
Explanation: The lowest pressure in a laboratory is 4.0×10^-11Pa
Using Ideal gas equation
PV = nRT
P= 4.0×10^-11Pa
V= 0.020m^3
T= 20+273= 293k
n=number of moles = m/A
Where m is the number of molecules and A is the Avogradro's number=6.02×10²³/mol
R=8.314J/(mol × K)
PV= m/A(RT)
4.0×10^-11 ×0.020 = m/6.02×10²³(8.314×293)
m = 4.0×10^-11×0.020×6.02×10^23 / (8.314×293)
m = 1.98×10^8 molecules
Therefore,the number of molecules is 1.98×10^8
