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Murljashka [212]
3 years ago
7

How are the conditions at which phases are in equilibrium represented on a phase diagram?

Chemistry
1 answer:
insens350 [35]3 years ago
7 0

How are the conditions at which phases are in equilibrium represented on a phase diagram?

Image result for How are the conditions at which phases are in equilibrium represented on a phase diagram?

Along the line between liquid and solid, the melting temperatures for different pressures can be found. The junction of the three curves, called the triple point, represents the unique conditions under which all three phases exist in equilibrium together. Phase diagrams are specific for each substance and mixture.

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An ocean trench .
Klio2033 [76]

Answer:

C. Occurs where a plate is moving down.

Explanation:

Ocean trenches are steep depressions in the deepest parts of the ocean where old ocean crust from one tectonic plate is pushed beneath another plate, raising mountains, causing earthquakes, and forming volcanoes on the seafloor and on land.

Please mark as Brainliest! :)

7 0
3 years ago
Read 2 more answers
Atoms of elements at the top of a group on the periodic table are smaller than the atoms of elements at the bottom of the group.
Serjik [45]

I think the correct answer would be the last one.

7 0
3 years ago
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Tin has ten stable isotopes. The heaviest, 124Sn, makes up 5.80% of naturally occuring tin atoms. How many atoms of 124Sn are pr
matrenka [14]

The average atomic mass of Sn is 118.71 g/mol

the percentage of heaviest Sn is 5.80%

the given mass of Sn is 82g

The total  moles of Sn will be = mass / atomic mass = 82/118.71=0.691

Total atoms of Sn in 82g = 6.023X10^{23}X0.691=4.16X10^{23}

the percentage of heaviest Sn is 5.80%

So the total atoms of Sn^{124} = 5.80% X 4.16X10^{23}

Total atoms of Sn^{124}=2.41X10^{22} atoms

the mass of Sn^{124} will be = \frac{2.41X10^{22}X124}{6.023X10^{23}}=4.96g

5 0
3 years ago
What is the IMA of the lever pictured?<br><br><br><br> 0.18<br> 0.20<br> 0.90<br> 5
IceJOKER [234]
<span>The ideal mechanical advantage represents the number of times the input force is multiplied under ideal conditions, that is with no friction. Actual mechanical advantage on the other hand stands for the number of times the input force is multiplied. 
Hence; IMA (ideal mechanical advantage)=Le/Lr
The Lr =0.3 +1.2 = 1.5 and Le= 0.3
       = 0.3/1.5 = 1/5;
therefore the correct answer is 0.2</span>
6 0
3 years ago
Read 2 more answers
Assume the atmospheric pressure is 1 atm but the actual pressure is higher than 1 atm how will this error affect the calculated
ozzi
Answer : When we consider the atmospheric pressure as 1 atm then according to the ideal gas equation we can find out the molar mass of any unknown by this formula ;

PV=nRT

so if the pressure increases than 1 atm then we can see from the above equation that it will result in greater value for the number of moles (n) in the above equation.

While n = m/M where m is mass of the unknown in g and M is molecular mass.

So, if pressure is higher then it will result in molar mass of unknown which is much smaller.
6 0
3 years ago
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