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Doss [256]
3 years ago
8

Do elements of the halogen family lose one electron to become halide ions

Chemistry
1 answer:
lana66690 [7]3 years ago
5 0
Its on Google..."The group number of a representative element in the periodic table is related to the number of valence electrons it has. ... Elements of the halogen family lose one electron to become halide ions."
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How many moles are there in 3.612 x 1024 formula units of Na2SO4?
vitfil [10]

Answer:

<h3>Theanswer is 6 moles</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L}  \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{3.612 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\

We have the final answer as

<h3>6 moles</h3>

Hope this helps you

5 0
3 years ago
Without what do carbohydrates fats and proteins can not be changed into energy
stepan [7]

vitamins is the answer to your question

5 0
3 years ago
How many grams are in 116 mg? Express your answer numerically in grams
Lisa [10]

Answer:

0.116 grams

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4 0
2 years ago
Read 2 more answers
g A radioactive isotope of mercury, 197Hg, decays to gold, 197Au, with a disintegration constant of 0.0108hrs.-1. What % of the
weqwewe [10]

Answer:

7.49% of Mercury

Explanation:

Let N₀ represent the original amount.

Let N represent the amount after 10 days.

From the question given above, the following data were obtained:

Rate of disintegration (K) = 0.0108 h¯¹

Time (t) = 10 days

Percentage of Mercury remaining =?

Next, we shall convert 10 days to hours. This can be obtained as follow:

1 day = 24 h

Therefore,

10 days = 10 day × 24 h / 1 day

10 days = 240 h

Thus, 10 days is equivalent to 240 h.

Finally, we shall determine the percentage of Mercury remaining as follow:

Rate of disintegration (K) = 0.0108 h¯¹

Time (t) = 10 days

Percentage of Mercury remaining =?

Log (N₀/N) = kt /2.303

Log (N₀/N) = 0.0108 × 240 /2.303

Log (N₀/N) = 2.592 / 2.303

Log (N₀/N) = 1.1255

Take the anti log of 1.1255

N₀/N = anti log 1.1255

N₀/N = 13.3506

Invert the above expression

N/N₀ = 1/13.3506

N/N₀ = 0.0749

Multiply by 100 to express in percent.

N/N₀ = 0.0749 × 100

N/N₀ = 7.49%

Thus, 7.49% of Mercury will be remaining after 10 days

5 0
2 years ago
why would dry cleaners use nonpolar tetrachloroethylene, c2cl4, to get cheeseburger grease out of clothes?
Sergeeva-Olga [200]
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3 0
3 years ago
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