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Minchanka [31]
2 years ago
8

A West Virginia coal is burned at a rate of 8.02 kg/s. The coal has a sulfur content of 4.40 % and the bottom ash contains 2.80

% of the input sulfur. What is the annual rate (in kg/yr) of stack emissions of SO2
Chemistry
1 answer:
aleksley [76]2 years ago
5 0

Answer: The annual emission rate of SO2 is 1.08 × 10^{7} kg/yr

Explanation:

  • The rate <em>r</em> at which the coal is been burnt is 8.02 kg/s.
  • Amount of sulphur in the burning coal is given as 4.40 %

i.e., 4.4/100 × 8.02 = 0.353 kg/s. Which is equivalent to the rate at which the sulphur is been burnt.

  • Since the burning of sulphur oxidizes it to produce SO2, it follows that the non-oxidized portion of the sulphur will go with the bottom ash.

  • The bottom ash is said to contain 2.80 % of the input sulphur.

  • Hence the portion of the SO2 produced is 100 — 2.80 = 97.20 %.

  • The rate of the SO2 produced is percentage of SO2 × rate at high sulphur is been burnt.

  = 97.20/100 × 0.353 kg/s.

  = 0.343 kg/s.

  • To get the annual emission rate of SO2, we convert the kg/s into kg/yr.

1 kg/s = 1 kg/s × (60 × 60 × 24 × 365) s/yr

1 kg/s = 31536000 kg/yr

  • Therefore, 0.343 kg/s = 0.343 × 31536000 kg/yr

     = 10816848 kg/yr

     = 1.08 × 10^7 kg/yryr.

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The frequency of an x-ray wave is 3.0 x 1012MHz. Its wave speed is 3.0x 108m/s. Calculate the wavelength of the x-ray wave below
jasenka [17]

Answer: The wavelength of the x-ray wave is 10^{-10}m

Explanation:

To calculate the wavelength of light, we use the equation:

\lambda=\frac{c}{\nu}

where,

\lambda = wavelength of the light  = ?

c = speed of x-ray= 3.0\times 10^8m/s

\nu = frequency of x-ray = 3.0\times 10^{12}MHz=3.0\times 10^{18}Hz= 3.0\times 10^{18}s^{-1}     (1Hz=1s^{-1})

Putting in the values:

\lambda=\frac{3.0\times 10^8m/s}{3.0\times 10^{18}s^{-1}}=10^{-10}m

Thus the wavelength of the x-ray wave is 10^{-10}m

5 0
3 years ago
A sample of gold has a mass of 15.7 g and displaces 0.81 cm3 of eater in a graduated cylinder. What is the density of gold?
Ostrovityanka [42]

Answer: 19.4 g/cm3

Explanation: density is the relationship between mass over volume.

So density of gold is 15.7g/0.81cm3 = 19.4 g/cm3

3 0
3 years ago
if there are 4 grams of reactant,how many grams of product are produced by the chemical reaction. a.0 grams b.2 grams c.4 grams
Murrr4er [49]
4 grams , mass cannot be created or destroyed. it has to be the same on both sides of the equation
5 0
3 years ago
The decomposition of HBr(g) into elemental species is found to have a rate constant of 4.2 ×10−3atm s−1. If 2.00 atm of HBr are
Dennis_Churaev [7]

Answer:

7,94 minutes

Explanation:

If the descomposition of HBr(gr) into elemental species have a rate constant, then this reaction belongs to a zero-order reaction kinetics, where the r<em>eaction rate does not depend on the concentration of the reactants. </em>

For the zero-order reactions, concentration-time equation can be written as follows:

                                          [A] = - Kt + [Ao]

where:

  • [A]: concentration of the reactant A at the <em>t </em>time,
  • [A]o: initial concentration of the reactant A,
  • K: rate constant,
  • t: elapsed time of the reaction

<u>To solve the problem, we just replace our data in the concentration-time equation, and we clear the value of t.</u>

Data:

K = 4.2 ×10−3atm/s,  

[A]o=[HBr]o= 2 atm,  

[A]=[HBr]=0 atm (all HBr(g) is gone)

<em>We clear the incognita :</em>

[A] = - Kt + [Ao]............. Kt =  [Ao] - [A]

                                        t  = ([Ao] - [A])/K

<em>We replace the numerical values:</em>

t = (2 atm - 0 atm)/4.2 ×10−3atm/s = 476,19 s = 7,94 minutes

So, we need 7,94 minutes to achieve complete conversion into elements ([HBr]=0).

6 0
2 years ago
Increasing the amount of current flowing through a wire strengthens
vagabundo [1.1K]

Answer:

It will strengthen Electromagnetism

8 0
2 years ago
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