<span>The two elements that are responsible for acid rain are sulphur and nitrogen.</span>
(H+)(OH-) = Kw
kw= 1 x10^-14
OH-= 1 x10 ^-11
(H+)= KW / OH-
concentration of H+ = (1x10^-14) /.(1 x 10 ^-11) = 1 x10 ^-3
Ph= -log (H+)
PH=-log ( 1 x 10 ^-3) = 3 therefore the solution is acidic since the PH less than 7
Answer:
24.6g of NaCl
Explanation:
Expression of the reaction:
2NaCl → 2Na + Cl₂
Given parameters:
Mass of Cl₂ = 15g
Unknown:
Mass of NaCl = ?
Solution:
To solve this problem, we have to use mole relationships.
Find the number of moles of the mass of the given specie;
Number of moles =
Molar mass of Cl₂ = 2(35.5) = 71g/mol
Number of moles =
= 0.21mole
Now;
From the balanced reaction equation;
1 mole of Cl₂ is produced from 2 moles of NaCl;
0.21 mole of Cl₂ will be produced from 0.21 x 2 = 0.42mole of NaCl
So,
Mass of NaCl = number of moles x molar mass
Molar mass of NaCl = 23 + 35.5 = 58.5g/mol
Mass of NaCl = 0.42 x 58.5 = 24.6g of NaCl
Answer : Hydrogen-bonding, Dipole-dipole attraction and London-dispersion force.
Explanation :
The given molecule is
.
Three types of inter-molecular forces are present in this molecule which are Hydrogen-bonding, Dipole-dipole attraction and London-dispersion force.
- Hydrogen-bonding : when the partial positive end of hydrogen is bonded with the partial negative end of another molecule like, oxygen, nitrogen, etc.
- Dipole-dipole attraction : When the partial positively charged part of the molecule is interact with the partial negatively charged part of the molecule. For example : In case of HCl.
- London-dispersion force : This force is present in all type of molecule whether it is a polar or non-polar, ionic or covalent. For example : In case of Br-Br , F-F, etc
Hydrogen-bonding is present between the oxygen and hydrogen molecule.
Dipole-dipole forces is present between the carbon and oxygen molecule.
London-dispersion forces is present between the carbon and carbon molecule.
The number of joules released when 0.64g of steam are cooled from 125 c to 105 c is -26.112 joules
calculation
by use of Q=MCΔ T formula calculate the joules released where
Q( heat) =?
M (mass) = 0.64 g
C (specific heat capacity = 2.04 j/g/c
ΔT(change in temperature) = 105-125 =-20c
Q is therefore = 0.64 g x2.04 j/g/c x -20 c = -26.112 joules
it is okay to have negative value since the reaction is exothermic that is heat is released