Answer:
(1). Mole fraction = 0.152 for sulfur tetrafluoride gas.
Mole fraction = 0.848 For dinitrogen monoxide gas.
(2). Partial Pressure for dinitrogen monoxide gas = 187 kPa
Partial Pressure for sulfur tetrafluoride gas = 33.4 kpa.
(3). Total Partial Pressure = 220.4 kpa.
Explanation:
So, we are given the following data or parameters or information in the question above;
• Volume of the tank = 5.00L per tank;
• Temperature of the tank = 7.03°C;
• The mass of the content in the tank =
17.7g of dinitrogen monoxide gas and
7.77g of sulfur tetrafluoride gas.
So, we will be making use of the formulae below to calculate the MOLE FRACTION:
Moles, n= mass/molar mass and mole fraction = n(1)/ n(1) + n(2) per each constituents.
Moles, n1 = 17.7g of dinitrogen monoxide gas/ 44 grams per mole. =0.4023 moles.
Moles, n2 = 7.77g of sulfur tetrafluoride gas/ 108.1 grams per mole. = 0.07188 moles.
Total numbers of moles = n1 + n2 = 0.47415 moles
Mole fraction =0.4023 / 0.47415 = 0.848 of dinitrogen monoxide gas.
Mole fraction = 0.07188/0.47415 = 0.152 of sulfur tetrafluoride gas.
PART TWO: CALCULATE THE PARTIAL PRESSURE AND TOTAL PRESSURE BY USING THE FORMULA BELOW;
pressure × volume = number of moles × gas constant, R × temperature.
Pressure = n × R × T/ V.
For dinitrogen monoxide gas. ;
Partial Pressure = 0.4023 × 8.314 × 280.03 / 5 × 10^-3 = 187 kPa.
For sulfur tetrafluoride gas
Partial Pressure = 0.07188 × 8.314 ( × 280.03 / 5 × 10^-3. = 33.4 kpa.
(3). Total pressure = (187 + 33.4)kpa = 220.4 kpa
