Cations have fewer _____ than _____.
2 answers:
Answer:
C.Electrons,protons.
Explanation:
Cations:
When metal loos it electrons then it will form cations.
Ex:
Anion:
When metal gain electron then it will from anions.
Ex:
So from above we can say that ,the cations have fewer electrons than protons.Protons is also called as positive charged ions and electron are also called negatively charge ions.
SO the option is C is correct.
You might be interested in
Answer:
The radius of the wetter area expands at a rate of milimeters per second when radius is 150 milimeters.
Explanation:
From Geometry we remember that area of a circle is described by this expression:
(Eq. 1)
Where:
- Radius of the circle, measured in milimeters.
- Area of the circle, measured in square milimeters.
Then, the rate of change of the area in time is derived by concept of rate of change, that is:
(Eq. 2)
Where:
- Rate of change of radius in time, measured in milimeters per second.
- Rate of change of area in time, measured in square milimeters per second.
Now the rate of change of radius in time is cleared within equation above:
If we know that and
, then the rate of change of radius in time is:
The radius of the wetter area expands at a rate of milimeters per second when radius is 150 milimeters.
Answer:
a) v = 18.86 m / s, b) h = 8.85 m
Explanation:
a) For this exercise we can use the conservation of energy relations.
Starting point. Like the compressed spring
Em₀ = K_e + U = ½ k x² + m g x
the zero of the datum is placed at the point of the uncompressed spring
Final point. With the spring if compress
Em_f = K = ½ m v²
how energy is conserved
Em₀ = Em_f
½ k x² + m g x = ½ m v²
v² = x² + 2gx
let's reduce the magnitudes to the SI system
m = 500 g = 0.500 kg
x = -45 cm = -0.45 m
the negative sign is because the distance in below zero of the reference frame
let's calculate
v² = 0.45² + 2 9.8 (- 0.45)
v = √355.68
v = 18.86 m / s
b) For this part we use the conservation of energy with the same initial point and as an end point at the point where the rock stops
Em_f = U = m g h
Em₀ = Em_f
½ k x²2 + m g x = m g h
h = ½ x² + x
let's calculate
h = - 0.45
h = 8.85 m
measured from the point where the spring is uncompressed