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Andrei [34K]
3 years ago
14

Cations have fewer _____ than _____.

Physics
2 answers:
Ede4ka [16]3 years ago
4 0

Answer:

C.Electrons,protons.

Explanation:

Cations:

 When metal loos it electrons then it will form cations.

Ex:Na^{+1}

Anion:

When metal gain electron then it will from anions.

Ex:F^{-1}

So from above we can say that ,the cations have fewer electrons than protons.Protons is also called as positive charged ions and electron are also called negatively charge ions.

SO the option is C is correct.

FrozenT [24]3 years ago
3 0
Cations are positively charged ions. And for positive charged ions, it means the positive charges, protons, are more than the negative charges, the electrons.

Therefore Cations have fewer electrons than protons.

So the answer is:    c. electrons; protons. 
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A rock hits a window and stops in 0.15 seconds. The net force on the rock is 58N during the collision. What is the magnitude of
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Answer:

The change in momentum is  \Delta p =   0.7 \ kg\cdot m \cdot s^{-1}

Explanation:

From the question we are told that

    The time taken for the stone to stop is \Delta  t = 0.15 \ seconds

    The net force on the rock is  F =  58 \ N

   

The impulse of the rock can be mathematically represented as

     I  =  F * \Delta t

Substituting values

     I  =  58 * 0.15

    I  =  0.7\  kg * m  * s^{-1}

Now impulse is defined as  the rate at which momentum change

   Hence the change in momentum \Delta p  of the rock is equal to the impulse of the rock

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       \Delta p =  I  =  0.7 \ kg\cdot m \cdot s^{-1}

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3 years ago
Why doesn't electric current flow through rubber?
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What is the electron configuration of this element? *for ne
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If you are at latitude 43 degrees north of Earth's equator, what is the angular distance (in degrees) from your zenith to the no
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Your zenith is 43 N of 90 deg (equator)

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2 years ago
A block of mass 14.9 kg is pulled to the right by an applied force of 39.4 N. If it moves with constant velocity, how much frict
lakkis [162]

The frictional force is 39.4 N

Explanation:

We can solve this problem by applying Newton's 2nd law of motion: in fact, the net force acting on the block is equal to the product between its mass and its acceleration. So we can write

\sum F = ma

where

\sum F is the net force

m is the mass

a is the acceleration

Here we know that the box is moving with constant velocity, so its acceleration is zero:

a=0

This means that the net force is also zero:

\sum F=0

The net force on the block is given by the applied force, forward, and the frictional force, backward:

\sum F = F_a-F_f=0

where

F_a=39.4 N is the applied force

F_f is the frictional force

Therefore, solving for F_f,

F_f=F_a=39.4 N

Learn more about friction:

brainly.com/question/6217246

brainly.com/question/5884009

brainly.com/question/3017271

brainly.com/question/2235246

#LearnwithBrainly

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