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3 years ago

15

Properties of light that define light as a wave?

2 answers:

MAVERICK [17]3 years ago

6 0

The first choices are correct, because the second choices could happen by things other than light.

Harlamova29_29 [7]3 years ago

6 0

I believe the correct answer from the two choices above is the first set of choice. Properties of light that define light as a wave are <span>Wavelength, </span>
<span>Amplitude, </span><span>Period, </span><span>Frequency and speed. These terms are used and calculated to define a light as a wave. Hope this answers the question.</span>

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When a piece of metal mass of 72.17 g is

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Answer:

Explanation:

The trick is in finding the volume.

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3 years ago

Photons with the highest energy have the longest period

xz_007 [3.2K]

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3 years ago

Read 2 more answers

Two blocks of masses M and 2M are initially traveling at the same speed v but in the opposite directions. They collide and stick

Hatshy [7]

Answer:

Explanation:

Given

Two masses M and 2 M with velocity v in opposite direction

After collision they stick together

Initial momentum

$P_i=Mv-2Mv$

final momentum

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Conserving momentum

$P_i=P_f$

$-Mv=3Mv'$

$v'=\frac{v}{3}$

i.e. system moves towards the direction of 2M mass

Initial kinetic Energy $K_1=\frac{1}{2}Mv^2+\frac{1}{2}2Mv^2$

$K_1=\frac{3}{2}Mv^2$

Final Kinetic Energy $K_2=\frac{1}{2}\cdot (3M)\cdot (\frac{v}{3})^2=\frac{3}{18}Mv^2$

loss of Energy $=K_1-K_2$

$=\frac{3}{2}Mv^2-\frac{3}{18}Mv^2$

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3 years ago

The production of heat by metabolic processes takes place throughout the volume of an animal, but loss of heat takes place only

Sever21 [200]

To solve this problem we will apply the concepts related to the change in length in proportion to the area and volume. We will define the states of the lengths in their final and initial state and later with the given relationship, we will extrapolate these measures to the area and volume

The initial measures,

$\text{Initial Length} = L$

$\text{Initial surface Area} = 6L^2$ (Surface of a Cube)

$\text{Initial Volume} = L^3$

The final measures

$\text{Final Length} = L_f$

$\text{Final surface area} = 6L_f^2$

$\text{Final Volume} = L_f^3$

Given,

$\frac{(SA)_f}{(SA)_i} = 2$

Now applying the same relation we have that

$(\frac{L_f}{L_i})^2 = 2$

$\frac{L_f}{L_i} = \sqrt{2}$

The relation with volume would be

$\frac{(Volume)_f}{(Volume)_i} = (\frac{L_f}{L_i})^3$

$\frac{(Volume)_f}{(Volume)_i} = (\sqrt{2})^3$

$\frac{(Volume)_f}{(Volume)_i} = (2\sqrt{2})$

$\frac{(Volume)_f}{(Volume)_i} = 2.83$

Volume of the cube change by a factor of 2.83

6 0

4 years ago