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PtichkaEL [24]
3 years ago
11

Is it possible for a system to have negative potentialenergy?

Physics
1 answer:
sineoko [7]3 years ago
5 0

Answer:

Yes, since the choice of the zero o potential energy is arbitrary.

Explanation:

The kinetic energy is due to the motion of the object. The expression for the kinetic energy is as follows;

KE=\frac{1}{2}mv^{2}

Here, m is the mass of the object and v is the velocity of the object.

The kinetic energy can not be negative as the velocity is squared. It can be zero and positive.

Potential energy: It is the energy is due to the position of the object.

The expression for the potential energy is as follows;

PE= mgh

Here, g is the acceleration due to gravity and height.

Height can be taken from the reference point, zero which can be taken below zero and above zero. Zero is taken as origin. Below zero, the height is taken as negative and above zero, the height is taken as positive.

The potential energy can be zero, positive and negative.

The total energy is the sum of kinetic energy and potential energy.

E= KE + PE

Here, KE is the kinetic energy and PE is the potential energy.

Therefore, the option (B) is correct.

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F=k_e  \frac{q_1 q_2}{r^2}
where
ke is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the two charges

We can see that the magnitude of the force is directly proportional to the charges. This means that when one of the charges is doubled, the magnitude of the electrostatic force will double as well, so the correct answer is
A) <span>The magnitude of the electrostatic force doubles</span>
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In the drawing, water flows from a wide section of a pipe to a narrow section. In which part of the pipe is the volume flow rate
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Volume flow rate is the same in both sections of the pipe

Explanation:

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A spring has a spring constant of 80 N/m. How much energy is stored in the spring when it is compressed 0.2 m past its natural l
Paha777 [63]
The energy of a compressed (or stretched) spring is given by

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A large crate is pushed across the floor with an effort of 45 Newtons. The box is pushed a distance of 3.5 meters. How much work
I am Lyosha [343]

Answer:

\boxed {\boxed {\sf 157.5 \ Joules }}

Explanation:

Work is equal to the product of force and distance.

W=F*d

The box is being pushed with an effort (force) of 45 Newtons and the distance is 3.5 meters.

F= 45 \ N \\d= 3.5 \ m

Substitute the values into the formula.

W= 45 \ N * 3.5 \ m

Multiply.

W= 157.5 \ N*m

  • 1 Newton meter is equal to 1 Joule
  • Our answer of 157.5 N*m equals 157.5 J

W= 157.5 \ J

<u>157.5 Joules </u> of work are done on the crate.

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