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PtichkaEL [24]
3 years ago
11

Is it possible for a system to have negative potentialenergy?

Physics
1 answer:
sineoko [7]3 years ago
5 0

Answer:

Yes, since the choice of the zero o potential energy is arbitrary.

Explanation:

The kinetic energy is due to the motion of the object. The expression for the kinetic energy is as follows;

KE=\frac{1}{2}mv^{2}

Here, m is the mass of the object and v is the velocity of the object.

The kinetic energy can not be negative as the velocity is squared. It can be zero and positive.

Potential energy: It is the energy is due to the position of the object.

The expression for the potential energy is as follows;

PE= mgh

Here, g is the acceleration due to gravity and height.

Height can be taken from the reference point, zero which can be taken below zero and above zero. Zero is taken as origin. Below zero, the height is taken as negative and above zero, the height is taken as positive.

The potential energy can be zero, positive and negative.

The total energy is the sum of kinetic energy and potential energy.

E= KE + PE

Here, KE is the kinetic energy and PE is the potential energy.

Therefore, the option (B) is correct.

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A mass of 1 kg is moving in a circle of radius 3.3 meters. What is the liner velocity v m/s that would give a Centripetal Force
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Answer:

The linear velocity of the object is 8.71 m/s.

Explanation:

Given;

mass of the object, m = 1 kg

radius of the circle, r = 3.3 meters

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Centripetal force is given by;

F_c = \frac{mv^2}{r}\\\\

where;

v is the linear velocity of the object

F_c = \frac{mv^2}{r}\\\\mv^2 = F_cr\\\\v^2 = \frac{F_cr}{m}\\\\v= \sqrt{\frac{F_cr}{m}} \\\\v= \sqrt{\frac{23*3.3}{1}}\\\\v = 8.71 \ m/s

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