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Vedmedyk [2.9K]

2 years ago

11

Electrical energy is sold by the kilowatt hour How much would it cost to heat a hot tub from 15 to 43

1 answer:

Alexeev081 [22]2 years ago

7 0

Answer:

hot tub is hot

Explanation:

dont get fried

You might be interested in

a. A 65-cm-diameter cyclotron uses a 500 V oscillating potential difference between the dees. What is the maximum kinetic energy

Sati [7]

Explanation:

Below is an attachment containing the solution.

8 0

3 years ago

An eccentric inventor attempts to levitate by first placing a large negative charge on himself and then putting a large positive

GuDViN [60]

Answer:

shirt is little attached to the body, it can come off and fly away

Explanation:

In electrostatics, charges of different signs attract and charges of the same sign repel.

In this case, when a negative charge is placed on it, both the inventor and the shirt are charged, therefore there is a repulsive force, also there is an attraction between the positive charge of the roof attracts the negative charge, such as the shirt. of weak the two forces not greater than the resistance of the walk.

As the shirt is little attached to the body, it can come off and fly away

3 0

3 years ago

A rocket in deep space has an empty mass of 150 kg and exhausts the hot gases of burned fuel at 2500 m/s. It is loaded with 600

3241004551 [841]

Answer:

$v(10\,s) \approx 775.387\,\frac{m}{s}$

$v(20\,s)\approx 1905.350\,\frac{m}{s}$

$v(30\,s) \approx 4023.595\,\frac{m}{s}$

Explanation:

The speed of the rocket is given the Tsiolkovsky's differential equation, whose solution is:

$v (t) = v_{o} - v_{ex}\cdot \ln \frac{m}{m_{o}}$

Where:

$v_{o}$ - Initial speed of the rocket, in m/s.

$v_{ex}$ - Exhaust gas speed, in m/s.

$m_{o}$ - Initial total mass of the rocket, in kg.

$m$ - Current total mass of the rocket, in kg.

Let assume that fuel is burned linearly. So that,

$m(t) = m_{o} + r\cdot t$

The initial total mass of the rocket is:

$m_{o} = 750\,kg$

The fuel consumption rate is:

$r = -\frac{600\,kg}{30\,s}$

$r = -20\,\frac{kg}{s}$

The function for the current total mass of the rocket is:

$m(t) = 750\,kg - (20\,\frac{kg}{s} )\cdot t$

The speed function of the rocket is:

$v(t) = - 2500\,\frac{m}{s}\cdot \ln \frac{750\,kg -(20\,\frac{kg}{s} )\cdot t}{750\,kg}$

The speed of the rocket at given instants are:

$v(10\,s) \approx 775.387\,\frac{m}{s}$

$v(20\,s)\approx 1905.350\,\frac{m}{s}$

$v(30\,s) \approx 4023.595\,\frac{m}{s}$

7 0

3 years ago

A car drives at a velocity of 6.8 m/s for 250 seconds. How far did it travel?

Leno4ka [110]

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

Here's the solution ~

As we know, Displacement =

$\qquad \sf \dashrightarrow \: velocity \times time$

$\qquad \sf \dashrightarrow \: 6.8 \times 250$

$\qquad \sf \dashrightarrow \: 1700 \: m$

<h3>OR </h3>

$\qquad \sf \dashrightarrow \: 1.7 \: km$

The car travelled 1700 meters ( 1.7 km )

8 0

2 years ago

Find the voltage across the 15 Q resistor.<br> [?] V<br><br> No links please

Margaret [11]

Answer:

Explanation:

same idea as before Liam, first, find the parallel resistance in 35 || 20

(35*20) / (35+20) = 700 / 55 = 12.727272 ohms

now add the 12.727272 + 15 = 27.727272 ohms total resistance

V = IR

10 = I * 27.727272

10 / 27.727272 = I

0.360655 = I

V = IR (again, but across the 15 ohm resistor)

V = 0.360655 * 15

V = 5.4098

4 0

2 years ago