Distance = (speed) x (time)
Distance = (20 m/s) x (500 s)
Distance = (20 x 500) (m·s / s)
Distance = 10,000 m
Yes, this is correct Answer.
Answer:
distance between both oasis ( 1 and 2) is 27.83 Km
Explanation:
let d is the distance between oasis1 and oasis 2
from figure
OC = 25cos 30
OE = 25sin30
OE = CD
Therefore BC = 30-25sin30
distance between both oasis ( 1 and 2) is calculated by using phytogoras theorem
in

PUTTING ALL VALUE IN ABOVE EQUATION


d = 27.83 Km
distance between both oasis ( 1 and 2) is 27.83 Km
Answer:
a)At the mean position
b)At the extremes positions
Explanation:
Given that mass is having oscillation motion.
We know that
1. At the mean position -The velocity of the mass is maximum and the acceleration of the mass is minimum.The net force on the mass will be zero.
2. At the extreme position-The velocity of the mass is minimum and the acceleration of the mass is maximum.The net force on the mass will not be zero.
Therefore
a)At the mean position
b)At the extremes positions