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muminat
3 years ago
12

A cab driver heads south with a steady speed of V,22.0 m/s tor t 3.00 min, then makes a right turn and travels at v225.0 m/s for

t2-2.40 min, and then drives northwest at v 30.0 m/s for 1.00 min. For this 6.40-min trip, calculate the following. Assume +x is In the eastward direction
(a) total vector displacement (Enter the magnitude in n and the direction in degrees south of west.) direvlion o south of west
(b) average speed (in m/s) m/s
(c) average velocity (Enter the magnitude in m/s and the direction in degrees south of west.) rmagnitude direction Im/'s o south of west
Physics
1 answer:
Lorico [155]3 years ago
6 0
The answer is c it makes the most sense
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Charge A and charge B are 3.00 m apart, and charge A is +1.44 C and charge B is +3.10 C. Charge C is located between them at a c
Sidana [21]

Answer:

the distance from charge A to C is r₁₃= 1.216 m

Explanation:

following Coulomb's law , the force exerted by 2 point charges between themselves is:

F= k*q₁*q₂/r₁₂² , where q is charge , r is distance and 1 and 2 represents the charge A and charge B respectively , k=constant

since C ( denoted as 3) is at equilibrium

F₁₃=F₂₃

k*q₁*q₃/r₁₃²=k*q₂*q₃/r₂₃²

q₁/r₁₃²=q₂/r₂₃²

r₁₃²/q₁=r₂₃²/q₂

r₂₃=r₁₃*√(q₂/q₁)

since C is at rest and is co linear with A and B ( otherwise it would receive a net force in either vertical or horizontal direction) , we have

r₁₃+r₂₃=d=r₁₂

r₁₃+r₁₃*√(q₂/q₁)=d

r₁₃*(1+√(q₂/q₁))=d

r₁₃=d/(1+√(q₂/q₁))

replacing values

r₁₃=d/(1+√(q₂/q₁)) = 3.00 m/(1+√(3.10 C/1.44 C)) = 1.216 m

thus the distance from charge A to C is r₁₃= 1.216 m

7 0
3 years ago
Prove dimensionally that: PV=RT
Oduvanchick [21]

Ideal Gas Law PV = nRT

THE GASEOUS STATE
Pressure  atm
Volume  liters
n  moles
R  L atm mol^-1 K^-1
Temperature  Kelvin


pv = rt

divide both sides by v
pv/v = rt/v

p = rt/v

answer: p = rt/v




Ideal Gas Law: Density

PV = NRT
PV = mass/(mw)RT

mass/V = P (MW)/RT = density



Molar Mass:
Ideal Gas Law PV = NRT
PV = mass/(MW) RT
MW = mass * RT/PV


Measures of Gases:
Daltons Law of Partial Pressures; is the total pressure of a mixture of gases equals the sum of the partial pressures of the individual gases.

Total = P_ A + P_ B

P_ A V = n_ A RT

P_ B V = n_ B R T



Partial Pressures in Gas Mixtures:
P_ total = P_ A + P_ B
P_ A = n_ A RT/V P_ B = n_ B RTV

P_ total = P_ A + P_ B = n_ total RT/V




For Ideal Gasses:


P_ A = n_ A RT/V P_ total = n_ toatal RT/V



P_ A/P_ total = n_ A RTV/n_ total RTV


= n_ A/n_ total = X_ A





Therefore, P_ A = X_ A P_ total.



PV = nRT


P pressure

V volume


n Number of moles


R Gas Constant


T temperture (Kelvin.).







Hope that helps!!!!!! Have a great day : )

4 0
3 years ago
HEY CAN ANYONE PLS PLS ANSWER DIS I RLY NEED IT
jeka94
Place the object in an electronic balance and measure its mass.
Place a measured amount of water in the cylinder.
Place the object in the cylinder so that it’s fully submerged.
Measure the new level of the liquid and subtract the original level. This is equal to the volume of the object.

Density = mass / volume.
8 0
3 years ago
An atomic scients was studying an atom and through experimentation found that the total negative charge of the
lys-0071 [83]

this atom has nine electrons

Explanation:

since electrons are found outside the nucleus of an atom and they are negatively charged

5 0
3 years ago
What is the acceleration of a 68 kg block of
S_A_V [24]

Answer:

Explanation:

Formula of acceleration a = fm

A = 68 x 386

= 26248

8 0
3 years ago
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