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muminat
3 years ago
12

A cab driver heads south with a steady speed of V,22.0 m/s tor t 3.00 min, then makes a right turn and travels at v225.0 m/s for

t2-2.40 min, and then drives northwest at v 30.0 m/s for 1.00 min. For this 6.40-min trip, calculate the following. Assume +x is In the eastward direction
(a) total vector displacement (Enter the magnitude in n and the direction in degrees south of west.) direvlion o south of west
(b) average speed (in m/s) m/s
(c) average velocity (Enter the magnitude in m/s and the direction in degrees south of west.) rmagnitude direction Im/'s o south of west
Physics
1 answer:
Lorico [155]3 years ago
6 0
The answer is c it makes the most sense
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Explanation:

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6 0
1 year ago
a hunter 412.5m from a cliff moves a distance x towards the cliff and fires a gun. he hears the echo from the cliff after 2.2sec
Inessa [10]

Answer: 49.5 m

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s=\frac{d}{t} (1)

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s=330 m/s is the speed of sound in air (taking into account this value may vary according to the medium the sound wave travels)

d=412.5 m-x since we are told th hunter was initially 412.5 meters from the cliff and then moves a distance x towards the cliff

t=\frac{2.2 s}{2}=1.1 s Since the time given as data (2.2 s) is the time it takes to the sound wave to travel from the hunter's gun and then go back to the position where the hunter is after being reflected by the cliff

Having this information clarified, let's isolate d and then find x:

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Finding x:

x=49.5 m This is the distance at which the hunter is from the cliff.

3 0
3 years ago
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