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Kaylis [27]
2 years ago
15

WILL MARK BRAINLIST

Physics
1 answer:
ryzh [129]2 years ago
3 0

Answer:

Definition of envelop

transitive verb

1: to enclose or enfold completely with or as if with a covering

2: to mount an attack on (an enemy's flank)

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Standing on a mountain, you look towards another mountain 6.00 km away, on which there are two persons standing 1.00 meter apart
allsm [11]

Answer:

No.

Explanation:

We shall solve this problem by calculating the resolving power of eye for given wavelength

Resolving Power of eye = \frac{1.22\lambda }{D}

Where λ is wave length of light and D is diameter of eye.

λ is 600 nm and D is 3.5 mm . Put these values in the given formula

Resolving Power = \frac{1.22\times 600\times 10^{-9} }{3.5\times 10^{-3}}\\

=209.14 \times 10^{-6}radian

From the formula

Φ = \frac{L}{D}[/tex]

Where Ф is resolving power . If L be distance between two points that can be resolved at distance D. D is 6 km or 6000 m .

209.14  \times 10^{-6}=\frac{L}{6000}\\

L= 1.254 m

So minimum distance that can be resolved is 1.254 m.

5 0
3 years ago
A particle with a charge of 5 × 10–6 C and a mass of 20 g moves uniformly with a speed of 7 m/s in a circular orbit around a sta
creativ13 [48]

Answer:

r = 0.22m

Explanation:

To find the radius of the circular trajectory, you first take into account that the centripetal force of the charged particle, is equal to the electric force between the particle that is moving and the particle at the center of the orbit.

Then, you have:

F_c=F_e=ma_c      (1)

m: mass of the particle = 20g = 20*10-3 kg

ac: centripetal acceleration = ?

q: charge of the particle = 5*10^-6C

Fe: electric force between the charges

The electric force is given by:

F_e=k\frac{qq'}{r^2}             (2)

r: radius of the orbit

q': charge of the particle at the center of the orbit = -5*10^-6C

Furthermore, the centripetal acceleration is:

a_c=\frac{v^2}{r}                 (3)

v: speed of the particle = 7m/s

You replace the expressions (2) and (3) in the equation (1) and solve for r:

k\frac{qq'}{r^2}=m\frac{v^2}{r}\\\\r=\frac{kqq'}{mv^2}

Finally, you replace the values of all parameters in the previous expression:

r=\frac{(8.98*10^9Nm^2/C^2)(5*10^{-6}C)(5*10^{-6}C)}{(20*10^{-3}kg)(7m/s)^2}\\\\r=0.22m

The radius of the circular trajectory is 0.22m

5 0
3 years ago
1. Should water be classified as renewable or nonrenewable? Explain your reasoning.
Alinara [238K]

Answer:

Renewable Resource Hydropower is renewed by the Earth's hydrologic cycle. Water has also been considered renewable, but overpumping of groundwater is depleting aquifers, and pollution threatens the use of many water resources, showing that the consequences of resource use are not always simple depletion.For low-mass stars (left hand side), after the helium has fused into carbon, the core collapses again. As the core collapses, the outer layers of the star are expelled. A planetary nebula is formed by the outer layers. The core remains as a white dwarf and eventually cools to become a black dwarf. inexpensive compared to coal ... o Two types of coal—low rank (pollutes more), and high rank.

Explanation:

4 0
3 years ago
A child and sled with a combined mass of 48.8 kg slide down a frictionless hill that is 7.05 m high. If the sled starts from res
nexus9112 [7]

Answer:

Speed at bottom of the hill (v) = 11.74 m/s

Explanation:

Given:

Combined mass = 48.8 kg

Height h = 7.05 m

Find:

Speed at bottom of the hill (v)

Computation:

v² = 2gh

v = √2 x 9.8 x 7.05

v = √138.18

v = 11.74 m/s

Speed at bottom of the hill (v) = 11.74 m/s

7 0
3 years ago
he drag characteristics of a torpedo are to be studied in a water tunnel using a 1 : 7 scale model. The tunnel operates with fre
dusya [7]

Answer:20.03 m/s

Explanation:

Given

L_r=1:7

velocity of Prototype v_p=53 m/s

Taking Froude number same for both flow as it is a dimensionless number for different flow regimes in open Flow

(\frac{v_m}{\sqrt{L_mg}})=(\frac{v_p}{\sqrt{L_pg}})

v_m=v_p\times \sqrt{\frac{L_m}{L_p}}

v_m=53\times \frac{1}{\sqrt{7}}

v_m=20.03 m/s

           

4 0
3 years ago
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