Answer:
Explanation:
mass of probe m = 474 Kg 
initial speed u = 275 m /s 
force acting on it F = 5.6 x 10⁻² N 
displacement s = 2.42 x 10⁹ m 
A )
initial kinetic energy = 1/2 m u²  , m is mass of probe. 
= .5 x 474 x 275²
= 17923125 J  
B )
work done by engine 
= force x displacement 
= 5.6 x 10⁻² x 2.42 x 10⁹
= 13.55 x 10⁷ J  
C ) Final kinetic energy 
= Initial K E + work done by force on it 
= 17923125 +13.55 x 10⁷ 
= 1.79 x 10⁷ + 13.55 x 10⁷
= 15.34 x 10⁷ J 
D ) If v be its velocity 
1/2 m v² = 15.34 x 10⁷
 1/2 x 474 x v² =  15.34 x 10⁷
v² = 64.72 x 10⁴
v = 8.04 x 10² m /s
= 804 m /s 
 
        
             
        
        
        
Answer:
turning a doorknob 
Explanation:
it will snap back once you release it.
 
        
                    
             
        
        
        
Answer:
3. Higher in some places and lower in other places 
 
        
                    
             
        
        
        
The velocity of the boat after the package is thrown is 0.36 m/s.
<h3>
Final velocity of the boat</h3>
Apply the principle of conservation of linear momentum;
Pi = Pf
where;
- Pi is initial momentum
- Pf is final momentum
v(74 + 135) = 15 x 5
v(209) = 75
v = 75/209
v = 0.36 m/s
Thus, the velocity of the boat after the package is thrown is 0.36 m/s.
Learn more about velocity here: brainly.com/question/6504879
#SPJ1
 
        
             
        
        
        
Split the operation in two parts. Part A) constant acceleration 58.8m/s^2, Part B) free fall.
Part A) 
Height reached, y = a*[t^2] / 2 = 58.8 m/s^2 * [7.00 s]^2 / 2 = 1440.6 m
Now you need the final speed to use it as initial speed of the next part.
Vf = Vo + at = 0 + 58.8m/s^2 * 7.00 s = 411.6 m/s
Part B) Free fall
Maximum height, y max ==> Vf = 0
Vf = Vo - gt ==> t = [Vo - Vf]/g = 411.6 m/s / 9.8 m/s^2 = 42 s
ymax = yo + Vo*t - g[t^2] / 2
ymax = 1440.6 m + 411.6m/s * 42 s - 9.8m/s^2 * [42s]^2 /2
ymax = 1440.6 m + 17287.2m - 8643.6m = 10084.2 m
Answer: ymax = 10084.2m