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3 years ago

How much farther will a car traveling at 100 km/s skid than the same car traveling at 50 km/s?

Physics

1 answer:

Roman55 [17]3 years ago

6 0

Answer:

option A

Explanation:

given,

speed of car 1 = 100 Km/s

speed of car 2 = 50 Km/s

final speed = 0 Km/s

now,

skid mark when the car is moving at 100 Km/s

using equation of motion

v² = u² + 2 a s₁

0² = 100² - 2 a s₁

100² = 2 a s₁

$s_1 = \dfrac{100^2}{2a}$ ..........(1)

now,

skid mark when the car is moving at 50 Km/s

using equation of motion

v² = u² + 2 a s₂

0² = 50² - 2 a s₂

50² = 2 a s₂

$s_2 = \dfrac{50^2}{2a}$ ..........(2)

dividing equation (1)/ (2)

$\dfrac{s_1}{s_2} = \dfrac{100^2}{50^2}$

$\dfrac{s_1}{s_2} =4$

s₁ = 4 s₂

Hence, the skid mark for 100 Km/s is four time as far as 50 Km/s

The correct answer is option A

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Read the scenario. A car travels 25 m/s forward for 10 s. Which option accurately identifies the measurements within the scenari

Phantasy [73]

Explanation:

It is given that,

A car travels 25 m/s forward for 10 s.

Solution,

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Out of given option,s the correct option is (c) "The measurement 25 m/s is the only vector quantity because it is a measurement of speed".

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3 years ago

Define what is boyleâs law?

lawyer [7]

Answer:

Volume of given mass of gas is inversely proportional to pressure of gas

Explanation:

Boyle's law: It states that the volume of given mass of gas is inversely proportional to the pressure of gas at constant temperature.

Mathematical representation:

Suppose, a gas of mass m

T=Constant temperature

V=Volume of gas

P=Pressure of gas

Then, $V\propto\frac{1}{P}$

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3 years ago

The ideal mechanical advantage of a pulley system is equal to the?

marishachu [46]

Answer: The correct answer is "Number of rope segments supporting the load".

Explanation:

Mechanical advantage: It is defined as the ratio of the force produced by a machine to the force applied on the machine. The ideal mechanical advantage of a machines is mechanical advantage in the absence of friction.

The ideal mechanical advantage of a pulley system is equal to the number of rope segments which is supporting the load. More the rope segments, It is more helpful to do the lifting the work.

It means that less force is needed for this task to complete.

Therefore, the correct option is (C).

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3 years ago

Read 2 more answers

A 750-newton person stands in an elevator that is

blondinia [14]

When an elevator is accelerating downward, the normal force is equal to mg-ma (hence you feel a little lighter when accelerating downwards)

Therefore, the upward force of the elevator floor on the person must be less than 750N

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3 years ago

Let’s say I am in a bumper car and have a velocity of 14 m/s, driving in the positive x-direction. I and my bumped car have a ma

AlekseyPX

Answer:

160 kg

12 m/s

Explanation:

$m_1$ = Mass of first car = 120 kg

$m_2$ = Mass of second car

$u_1$ = Initial Velocity of first car = 14 m/s

$u_2$ = Initial Velocity of second car = 0 m/s

$v_1$ = Final Velocity of first car = -2 m/s

$v_2$ = Final Velocity of second car

For perfectly elastic collision

$m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}\\\Rightarrow m_2v_2=m_{1}u_{1}+m_{2}u_{2}-m_{1}v_{1}\\\Rightarrow m_2v_2=120\times 14+m_2\times 0-(120\times -2)\\\Rightarrow m_2v_2=1920\\\Rightarrow m_2=\frac{1920}{v_2}$

Applying in the next equation

$v_2=\frac{2m_1}{m_1+m_2}u_{1}+\frac{m_2-m_1}{m_1+m_2}u_2\\\Rightarrow v_2=\frac{2\times 120}{120+\frac{1920}{v_2}}\times 14+\frac{m_2-m_1}{m_1+m_2}\times 0\\\Rightarrow \left(120+\frac{1920}{v_2}\right)v_2=3360\\\Rightarrow 120v_2+1920=3360\\\Rightarrow v_2=\frac{3360-1920}{120}\\\Rightarrow v_2=12\ m/s$

$m_2=\frac{1920}{v_2}\\\Rightarrow m_2=\frac{1920}{12}\\\Rightarrow m_2=160\ kg$

Mass of second car = 160 kg

Velocity of second car = 12 m/s

5 0

3 years ago