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Nutka1998 [239]
3 years ago
9

How much farther will a car traveling at 100 km/s skid than the same car traveling at 50 km/s?

Physics
1 answer:
Roman55 [17]3 years ago
6 0

Answer:

option A

Explanation:

given,

speed of car 1 = 100 Km/s

speed of car 2 =  50 Km/s

final speed = 0 Km/s

now,

skid mark when the car is moving at 100 Km/s

using equation of motion

v² = u² + 2 a s₁

0² = 100² -  2 a s₁

100² = 2 a s₁

s_1 = \dfrac{100^2}{2a}..........(1)

now,

skid mark when the car is moving at 50 Km/s

using equation of motion

v² = u² + 2 a s₂

0² = 50² -  2 a s₂

50² = 2 a s₂

s_2 = \dfrac{50^2}{2a}..........(2)

dividing equation (1)/ (2)

\dfrac{s_1}{s_2} = \dfrac{100^2}{50^2}

\dfrac{s_1}{s_2} =4

   s₁ = 4 s₂

Hence, the skid mark for 100 Km/s is four time as far as 50 Km/s

The correct answer is option A

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2 kg<br> Use 10 m/s2 for g
Iteru [2.4K]

Answer:

See below

Explanation:

At point A    the PE = mgh = 2 * 10 * 1 = 20 J

  at point B, all of the PE , 20 J , is converted to Kinetic Energy

KE = 1/2 m v^2

20 = 1/2 (2)(v^2 )

20 = v^2     v = sqrt 20 = 4.47 m/s

for the friction part

 vf = vo t  + 1/2 a t^2      vf = final velocity = 0 (stopped)

                                       vo = original velocity = 4.47 m/s  

                                         a = -1 m/s^2

  0 = 4.47 t + 1/2 (-1) t^2

            - .5t^2  + 4.47 t = 0

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6 0
1 year ago
A small metal sphere has a mass of 0.11 g and a charge of -21.0 nC . It is 10 cm directly above an identical sphere with the sam
GrogVix [38]

Answer:

A. the magnitude of the force between the spheres is 3.97 x 10⁻⁴ N

B. the magnitude of its initial acceleration is 5.83 m/s²

Explanation:

given information:

metal sphere's mass, m = 0.1 g = 1 x 10⁻⁴ kg

charge, q = -21 nC = -2.1 x 10⁻⁸

r = 10 cm = 0.1 m

What is the magnitude of the force between the spheres?

F₁₂ = k q₁q₂/r²

     = ( 9 x 10⁹) (-2.1 x 10⁻⁸)²/(0.1)²

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If the upper sphere is released, it will begin to fall. What is the magnitude of its initial acceleration?

mg - F₁₂ = ma

a = g - (F₁₂/m)

   = 9.8 - (3.97 x 10⁻⁴/1 x 10⁻⁴)

   = 5.83 m/s²

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