<h2>
Option A is the correct answer.</h2>
Explanation:
Here velocity of ball and bat are in opposite direction.
Velocity of ball = 40 m/s
Velocity of bat = 18 m/s
Since they are in opposite direction relative velocity is given by,
Relative velocity = 40 + 18 = 58 m/s
Distance to home plate = 18 m
We have
Displacement = Velocity x Time
18 = 58 x Time
Time = 0.3 seconds
Option A is the correct answer.
Answer:
Explanation:
See the file attached .
b ) Range of projectile
= u²sin2θ / g
= 42² sin32 x 2 / g
= 42² sin64 / 9.8
= 161.8 m
c )
Max height = u² sin²32 / 2 g
= 42² sin²32 / 2x 9.8
= 25.27 m .
PART A)
magnetic field lines always originates from North pole and terminates at south pole
So here the two poles will attract each other and field lines are shown in the figure
Part B)
As we know that magnetic field lines originates from north pole and terminates at south pole so here upper end is north pole and lower end is south pole
The answer is d) 20 m.
The depth of pond is 20 m if it seems to be 10 m.
The formula relating real depth and app. depth :
In this case, refractive index has to be an whole number for real depth to give a whole number for app. depth.
- Then, real depth must be a multiple of 10, but refractive index cannot be 1
- The option is 20 m
Answer
given,
v = 128 ft/s
angle made with horizontal = 30°
now,
horizontal component of velocity
vx = v cos θ = 128 x cos 30° = 110.85 ft/s
vertical component of velocity
vy = v sin θ = 128 x sin 30° = 64 m/s
time taken to strike the ground
using equation of motion
v = u + at
0 =-64 -32 x t
t = 2 s
total time of flight is equal to
T = 2 t = 2 x 2 = 4 s
b) maximum height
using equation of motion
v² = u² + 2 a h
0 = 64² - 2 x 32 x h
64 h = 64²
h = 64 ft
c) range
R = v_x × time of flight
R = 110.85 × 4
R = 443.4 ft