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Juli2301 [7.4K]
2 years ago
15

A centrifuge rotates so that 0. 25 m from the center is traveling at 343 m/s (the speed of sound). How many RPM is this? What is

its angular velocity?
Physics
1 answer:
andrew-mc [135]2 years ago
8 0

Answer:

[13,101 RPM]

[1372 rad/s]

Explanation:

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What's at the bottom of the black hole? Explain .​
Brilliant_brown [7]

Answer:

Unknown

Explanation:

By definition, we can't observe what's inside there, because no light – no information of any kind – can escape a black hole. But astrophysical theories suggest that, at the core of a black hole, all the black hole's mass is concentrated into a tiny point of infinite density. This point is known as a singularity.

7 0
2 years ago
A small ball with mass 1.20 kg is mounted on one end of a rod 0.860 m long and of negligible mass. The system rotates in a horiz
Rufina [12.5K]

Answer:

0.88752 kgm²

0.02236 Nm

Explanation:

m = Mass of ball = 1.2 kg

L = Length of rod = 0.86 m

\theta = Angle = 90°

Rotational inertia is given by

I=mL^2\\\Rightarrow I=1.2\times 0.86^2\\\Rightarrow I=0.88752\ kgm^2

The rotational inertia is 0.88752 kgm²

Torque is given by

\tau=FLsin\theta\\\Rightarrow \tau=2.6\times 10^{-2}\times 0.86sin90\\\Rightarrow \tau=0.02236\ Nm

The torque is 0.02236 Nm

5 0
3 years ago
Any collection of things that have some influence on one another can be thought of as a system. When we talk about a system, we
Katen [24]

Answer:

B

Explanation:

Its B

6 0
3 years ago
A 20-lb force acts to the west while an 80-lb force acts 45° east of north. The magnitu 80 lb 70 lb 067 lb 100 lb
natulia [17]

Answer:

option C

Explanation:

given,

force act on west  = 20 lb

force act at 45° east of north = 80 lb

magnitude of force = ?

∑ F y  =  80 cos 45⁰

    F y =  56.57 lb

magnitude of forces in x- direction

∑ F x = -20 + 80 sin 45⁰

        = 36.57 lb

net force

F = \sqrt{F_x^2+F_y^2}

F = \sqrt{56.57^2+36.57^2}

F = 67.36 lb≅ 67 lb

hence, the correct answer is option C

4 0
2 years ago
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okkiikkkkkkkkoiiiiiiii8iiii

5 0
2 years ago
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