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ANTONII [103]
3 years ago
5

A man weighs 90 N on the surface of earth of radius R at what height above the surface of earth is weight will be 40 N.

Physics
1 answer:
lapo4ka [179]3 years ago
4 0

Answer:

3/2 R

Explanation:

Let the Mass of man be m, Mass of earth be M.

By Newtons, law of gravitation,

F = GMm/R^2, Where G is gravitational constant

90 = GMm/R^2

When man weighs 40N,

GMm/(New R)^2 = 40

= 4/9 (90)

GMm/(New R)^2 = 4/9 (GMm/R^2)

(New R)^2 = 9/4 R^2

New R = 3/2 R

Therefore, height is <u>3</u><u>/</u><u>2</u><u> </u><u>R</u>

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Ú=F/R

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What is the equivalent resistance of the circuit?
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A balloon is a sphere with a radius of 5.0 m. the force of air against the walls of the balloon is 45 n. what is the air pressur
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The formulas and procedures that we will use to solve this problem are:

  • a = 4 * π * r²
  • P = F/a

Where:

  • a = area of the sphere
  • r = radius
  • π = mathematical constant
  • P = Pressure
  • F = Force
  • a = surface area

Information about the problem:

  • r = 5.0 m
  • F = 45 N
  • 1 Pa = N/m²
  • 1 N = kg * m/s²
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Using the formula of the sphere area we get:

a = 4 * π * r²

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Applying the pressure formula we get:

P = F/a

P = 45 N/314.16 m²

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<h3>What is pressure?</h3>

It is a physical quantity that expresses the force applied on the area of a surface.

Learn more about pressure at: brainly.com/question/26269477

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