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ANTONII [103]
3 years ago
5

A man weighs 90 N on the surface of earth of radius R at what height above the surface of earth is weight will be 40 N.

Physics
1 answer:
lapo4ka [179]3 years ago
4 0

Answer:

3/2 R

Explanation:

Let the Mass of man be m, Mass of earth be M.

By Newtons, law of gravitation,

F = GMm/R^2, Where G is gravitational constant

90 = GMm/R^2

When man weighs 40N,

GMm/(New R)^2 = 40

= 4/9 (90)

GMm/(New R)^2 = 4/9 (GMm/R^2)

(New R)^2 = 9/4 R^2

New R = 3/2 R

Therefore, height is <u>3</u><u>/</u><u>2</u><u> </u><u>R</u>

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\dfrac{dz}{dt}=0.65\ ft/s

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