Question

Suppose you walk into a sauna that has an ambient temperature of 48.0°C. (a) Calculate the rate of heat transfer in watts to you by radiation given your skin temperature is 37.0°C, the emissivity of skin is 0.98, and the surface area of your body is 1.30 m2.

Answer 1

Answer:99.84 W

Explanation:

Given

Ambient temperature $T_{\infty }=48^{\circ}C\approx 321\ K$

Temperature of skin $T=37^{\circ}C\approx 310\ K$

Skin emissivity $\epsilon =0.98$

Surface area $A=1.30\ m^2$

Rate of heat transfer is $Q=\epsilon A\sigma (T_0^4-T^4)$

$Q=0.98\times 1.30\times 5.67\times 10^{-8}((321)^4-(310)^4)$

$Q=99.84\ W$