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iVinArrow [24]
3 years ago
9

Answer this plsss A mobile phone operates at 900 MHz. What wavelength does it use?

Physics
1 answer:
Aleks [24]3 years ago
7 0

Answer:

The wavelength = 0.3333 meters at 900 MHz, therefore, = /4 = 0.08333 meters.

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Please help me! I don’t get this
goldfiish [28.3K]

The answer will be

(1) correct

(2) correct

(3) the force of the soccer ball on the net

(4) Will not change

Hope this help

4 0
3 years ago
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Suppose that a rectangular toroid has 1,500 windings and a self-inductance of 0.060 H. If the height of the rectangular toroid i
V125BC [204]

Answer:

Current in the toroid will be I=17.32\times 10^{-3}A

Explanation:

We have given number of winding in rectangular toroid N = 1500

Self inductance of toroid L = 0.06 H

Magnetic energy stored in toroid E=9\times 10^{-16}J

We have to find the current in the toroid

Magnetic energy stored is equal to E=\frac{1}{2}Li^2

9\times 10^{-6}=\frac{1}{2}\times 0.06\times I^2

I=17.32\times 10^{-3}A

So current in the toroid will be I=17.32\times 10^{-3}A

5 0
3 years ago
A bug walking on the circular rim of a flower
Mekhanik [1.2K]

Given parameters;

Time taken to complete a lap  = 8.667s

Radius of flower = 13.9cm

    convert to SI unit of m,  100cm = 1m

            13.9cm gives \frac{13.9}{100}   = 0.139m

Unknown  = speed

To solve this problem, we need to first find the circumference of the flower.

 Circumference of the circular flower  = 2 π r

    where r is the radius of the flower;

           Circumference  = 2 x 3.142 x 0.139 = 0.87m

Now to find the how fast the bug is travelling,

   Speed  = \frac{distance}{time}

Since the bug covered 1 lap, the distance is 0.87m

Now input the parameters and solve for speed;

    Speed  = \frac{0.87}{8.667}  = 0.1m/s

The bug is travelling at a speed of  0.1m/s

8 0
3 years ago
Does gravity has mass ?​
Natasha_Volkova [10]
No, gravity does not have mass, it behaves like a particle without mass
3 0
3 years ago
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Two sinusoidal waves, which are identical except for a phase shift, travel along in the same direction. The wave equation of the
Y_Kistochka [10]

Answer:

two sinusoidal waves, which are identical except for a phase shift, travel along in the same direction. The wave equation of the resultant wave is yR (x, t) = 0.70 m sin⎛ ⎝3.00 m−1 x − 6.28 s−1 t + π/16 rad⎞ ⎠ . What are the angular frequency, wave number, amplitude, and phase shift of the individual waves?

ω = 6.28 s − 1 ,

k = 3.00 m− 1 ,

φ = π rad,

A R = 2 A cos (φ 2 ) ,

A = 0.37 m

Explanation:

y1 ( x , t ) = A sin( k x − ω t +φ ) ,

y 2 ( x , t ) = A sin ( k x − ω t ) .

from the principle of superposition which states that when two or more waves combine, there resultant wave is the algebriac sum of the individual waves

y1 ( x , t ) = A sin( k x − ω t +φ ) ,   is generaL form of thw wave eqaution

A=amplitude

k=angular wave number

ω=angular frequency

φ =phase constant

k=2π/lambda

ω=2π/T

yR (x, t) = 0.70 m sin{3.00 m−1 x − 6.28 s−1 t + π/16 rad}....................*

two waves superposed to give the above, assuming they are moving in the +x direction

y1 ( x , t ) = A sin( k x − ω t +φ ) , .....................1

y 2 ( x , t ) = A sin ( k x − ω t ) ...........................2

adding the two equation will give

A sin( k x − ω t +φ )+A sin ( k x − ω t ) .................3

A( sin( k x − ω t +φ )+ sin ( k x − ω t ) ),......................4

similar to the following trigonometry identity

sina+sinb=2cos(a-b)/2sin(a+b)/2

let a= ( k x − ω t

b=k x − ω t +φ )

y(x,t)=2Acos(φ/2)sin(k x − ω t +φ/2)

k=3m^-1

lambda=2π/k=2.09m

ω=6.28= T=2π/6.28

T=1s

φ/2=π/16

φ=π/8rad

amplitude

2Acos(φ/2)=0.70 m

A=0.7/2cos(π/8)

A=0.37 m

6 0
3 years ago
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