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FinnZ [79.3K]
3 years ago
7

What will a spring scale read for the weight of a 75.0-kg woman in an elevator that moves upward with constant speed of 5.8 m/s

?
Physics
1 answer:
Sholpan [36]3 years ago
7 0
<span>On the scale the only external forces are the man's weight acting downwards and the normal force which the scale exerts back to support his weight. So F = Ma = mg + Fs The normal force Fs (which is actually the reading on the scale) = Ma + Mg But a = 0 So Fs = Mg which is just his weight. Fs = 75 * 9.8 = 735N</span>
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5 0
3 years ago
Hi please please help me you’ll get points and I’ll give you brainliest
leonid [27]

Answer:

see below

Explanation:

Question 1)

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Question 2)

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7 0
3 years ago
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ss7ja [257]
Hello friend!!

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LiRa [457]

Answer:

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8 0
3 years ago
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mel-nik [20]

Answer:u=\frac{v}{2}\sqrt{5-4sin\phi }

Explanation:

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and solving problem in Vertical and horizontal direction

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7 0
3 years ago
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