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Nonamiya [84]
4 years ago
10

The spreading of waves behind an aperture is more for long wavelengths and less for short wavelengths.Less for long wavelengths

and more for short wavelengths. Which is true and why?
Physics
1 answer:
Allisa [31]4 years ago
5 0

Answer:

Increase in wavelength of incident wave also increases the spread angle or spread of the interference pattern.

Explanation:

Solution:-

- The diffraction occurs when light bends in the same medium. The bending is the result of light waves "squeezing" through small openings or "curving" around sharp edges.

- Moreover, waves diffract best when the size of the diffraction opening (or grting or groove) corresponds to the size of the wavelength. Hence, light diffracts more through small openings than through larger openings.

- The formula for diffraction shows a direct relationship between the angle of diffraction (theta) and wavelength:

                                         d sin (θ) = m λ

Where,

     λ : Wavelength , θ : The spread angle , d : Slit opening or grating

- We can see that the wavelength λ and spread angle θ are related proportionally. So if we increase the wavelength of incident wave we also increase the spread angle or spread of the interference pattern.

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The 10-kg block is held at rest on the smooth inclined plane by the stop block at A. If the10-g bullet is traveling at 300m/swhe
WARRIOR [948]

Answer:

6.8 mm

Explanation:

We are given that

Mass of block,m=10 kg

Mass of bullet,m_b=10 g=10\times 10^{-3} kg

1 kg=1000 g

Total mass of system,M=m+m_a=10+10\times 10^{-3}=10.01kg

Speed of bullet,u=300 m/s

\theta=30^{\circ}

By law of conservation of momentum

m_bucos\theta=Mv

v=\frac{m_bvcos\theta}{M}=\frac{0.01\times 300cos30^{\circ}}{10.01}=0.259m/s

According to law of conservation of energy

Change in kinetic energy of system=Change in potential energy of system

\frac{1}{2}Mv^2-0=Mgh-0

\frac{1}{2}(10.01)(0.259)^2=10.01\times 9.8 h

Where g=9.8 m/s^2

h=\frac{(0.259)^2}{2\times 9.8}=0.0034m

1m=100 cm

h=0.0034\times 100=0.34 cm

Distance traveled by block=d=\frac{h}{sin\theta}=\frac{0.34}{sin30^{\circ}}=0.68 cm=6.8 mm

1cm=10 mm

4 0
4 years ago
how does the location of semiconductors on the periodic table differ from the locations of other element families​
Mekhanik [1.2K]

Answer:

Semi conductors are part of the fourth group in periodic table.

Explanation:

Periodic table is the arrangement of chemical elements on the basis of their atomic number. So all the elements with  respective valence electrons are placed in thir respective groups. . All the elements with valence electrons four are placed in the fourth group .Semi conductors is the common name given to the elements of 4th group. These elements dont have the tendency to either donate or accept.

The group 3 elements have three electrons in their valence shell and  hence have a tendency to donate. Whereas the group 5 elements having five valence electrons accept to satisfy thir octet. The semi conductors exist between 3rd and 5th groups exhibiting different properties according to the temperatures and excitations provided.

3 0
3 years ago
A parachutist's fall to Earth is determined by two opposing forces. A gravitational force of 605 N acts on the parachutist. Afte
Doss [256]

Answer:15.8 m/s

Explanation:

Given

Gravitational Force F_g=605 N

Air resistance F_d=689 N

mass of Parachutist =\frac{605}{9.8}=61.73 kg

Velocity after 3 s

v=u+at

v=0+9.8\times 3

v=29.4 m/s

Now Parachutist opens the parachute

Net for on Parachutist

605-689=-84

84 N drag force

therefore deceleration \frac{84}{61.73}=1.36 m/s^2

velocity after 10 s is

v_1=v+at

v_1=29.4-1.36\times 10

v_1=15.8 m/s

7 0
4 years ago
What type of boundries are the collision zones and subduction zones ?
IrinaK [193]
In a subduction zone<span>, the </span>subducting<span> plate, which is normally a plate with oceanic crust, moves beneath the other plate,</span>
3 0
4 years ago
A projectile, fired with unknown initial velocity, lands 20sec later on side of hill, 3000m away horizontally and 450m verticall
lorasvet [3.4K]

Explanation:

Given:

t = 20 seconds

x = 3000 m

y = 450 m

a) To find the vertical component of the initial velocity v_{0y}, we can use the equation

y = v_{0y}t - \frac{1}{2}gt^2

Solving for v_{0y},

v_{0y} = \dfrac{y + \frac{1}{2}gt^2}{t}

\:\:\:\:\:\:\:=\dfrac{(450\:\text{m}) + \frac{1}{2}(9.8\:\text{m/s}^2)(20\:\text{s})^2}{(20\:\text{s})}

\:\:\:\:\:\:\:=120.5\:\text{m/s}

b) We can solve for the horizontal component of the velocity v_{0x} as

x = v_{0x}t \Rightarrow v_{0x} = \dfrac{x}{t} = \dfrac{3000\:\text{m}}{20\:\text{s}}

or

v_{0x} = 150\:\text{m/s}

4 0
3 years ago
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