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3 years ago

A tennis ball of mass 0.060 kg travels horizontally at a speed of 25m/s. The ball hits a tennis

Physics

2 answers:

stepladder [879]3 years ago

7 0

It would be A because a is perfect

Novosadov [1.4K]3 years ago

5 0

I got A as the answer
Explanation:
Subtract the final velocity by the starting velocity and the divide by the time,
40-25= 15, so then divide 15 by the time ,50, to get 0.3. Now that the velocity is know u then multiple 0.3 by the mass of the tennis ball, 0.060, to get 0.018 Newton’s as the force being exerted.

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In what way are gravitational and electrical forces similar?

Nadusha1986 [10]

Answer:

D. Both occur between objects independently whether they are in contact or not.

Explanation:

- The gravitational force is a force that is exerted between two (or more) objects having mass. This force is always attractive and its magnitude is given by

$F=G\frac{m_1 m_2}{r^2}$

where G is the gravitational constant, m1 and m2 are the two masses, and r is the distance between the two masses.

- The electrical force is a force that is exerted between two (or more) objects having electrical charge. It can be either attractive or repulsive, depending on the sign of the two charges, and its magnitude is given by

$F=k\frac{q_1 q_2}{r^2}$

where k is the Coulomb's constant, q1 and q2 are the two charges, and r the distance between the two charges.

Looking at both formulas, we see that the two forces are present even when the two objects are not in contact with each other (in fact, r can assume any value in the formula). They are said to be non-contact forces. Therefore, the correct option is

D. Both occur between objects independently whether they are in contact or not.

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3 years ago

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Liula [17]

Answer:

it’s an example of a generator.

Explanation:

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2 years ago

All Physicsts over here plz help in these questions!!!!!!!!!

mrs_skeptik [129]

Hello!

First one we can use that PE=mgh so we have

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Second one we can use Newton’s Second Law
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g= 3.28*10^-2N/6*10^-3kg = 5.47m/s^2

Hope this helps. Any questions please ask. Thank you.

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