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3 years ago

A tennis ball of mass 0.060 kg travels horizontally at a speed of 25m/s. The ball hits a tennis

Physics

2 answers:

stepladder [879]3 years ago

7 0

It would be A because a is perfect

Novosadov [1.4K]3 years ago

5 0

I got A as the answer
Explanation:
Subtract the final velocity by the starting velocity and the divide by the time,
40-25= 15, so then divide 15 by the time ,50, to get 0.3. Now that the velocity is know u then multiple 0.3 by the mass of the tennis ball, 0.060, to get 0.018 Newton’s as the force being exerted.

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A steel beam that is 5.50 m long weighs 332 N. It rests on two supports, 3.00 m apart, with equal amounts of the beam extending

ElenaW [278]

Explanation:

The given data is as follows.

Length of beam, (L) = 5.50 m

Weight of the beam, ( $W_{b}$ ) = 332 N

Weight of the Suki, ( $W_{s}$ ) = 505 N

After crossing the left support of the beam by the suki then at some overhang distance the beam starts o tip. And, this is the maximum distance we need to calculate. Therefore, at the left support we will set up the moment and equate it to zero.

$\sum M_{o} = 0$

$-W_{s} \times x + W_{b} \times 1.5$ = 0

x = $\frac{W_{b} \times 1.5}{W_{s}}$

= $\frac{332 N \times 1.5}{505 N}$

= 0.986 m

Hence, the suki can come (2 - 0.986) m = 1.014 from the end before the beam begins to tip.

Thus, we can conclude that suki can come 1.014 m close to the end before the beam begins to tip.

8 0

3 years ago

Can an object have both kinetic energy and gravitational potential energy? Explain.

marin [14]

Energy flows with kinetic energy

8 0

2 years ago

The y component of the electric field of an electromagnetic wave travelling in the +x direction through vacuum obeys the equatio

notsponge [240]

Answer:

λ =8.57 μ m

Explanation:

Given that

Ey = 375 cos [kx − (2.20 × 10¹⁴ rad/s)t] N/C

Standard form

Ey=Eo cos[k x-ωt] N/C

By comparing the given equation with the standard wave equation

Eo = 375 N/C

ω = 2.20 × 10¹⁴ rad/s

We know that ω = 2 π f

$f=\dfrac{\omega}{2\pi }$

$f=\dfrac{2.2\times 10^{14}}{2\pi }\ Hz$

f=3.50×10¹³ Hz

We know that the velocity given as

V = f λ

λ =Wavelength

V=Speed = 3 x 10⁸ m/s

$\lambda =\dfrac{V}{f }$

$\lambda =\dfrac{3\times 10^8}{3.5\times 10^{13}}\ m$

λ =0.00000857 m ( 1 μ m = 10⁶ m)

λ =8.57 μ m

8 0

3 years ago

Which of the following is an exa example of a wave

maria [59]

Longitudinal waves

Transverse waves

Electromagnetic Waves

Water waves

Rope waves

LIght Waves

6 0

2 years ago

A wagon is rolling forward on level ground. Friction is negligible. The person sitting in the wagon is holding a rock. The total

Rudik [331]

Answer:

a) 0.41 m/s

b) 0.51 m/s

Explanation:

(a)

M = total mass of wagon, rider and the rock = 93.1 kg

V = initial velocity of wagon = 0.456 m/s

m = mass of the rock = 0.292 kg

v = velocity of rock after throw = 15.4 m/s

V' = velocity of wagon after rock is thrown

Using conservation of momentum

M V = m v + (M - m) V'

(93.1) (0.456) = (0.292) (15.4) + (93.1 - 0.292) V'

V' = 0.41 m/s

M = total mass of wagon, rider and the rock = 93.1 kg

V = initial velocity of wagon = 0.456 m/s

m = mass of the rock = 0.292 kg

v = velocity of rock after throw = - 15.4 m/s

V' = velocity of wagon after rock is thrown

Using conservation of momentum

M V = m v + (M - m) V'

(93.1) (0.456) = (0.292) (- 15.4) + (93.1 - 0.292) V'

V' = 0.51 m/s

6 0

3 years ago