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2 years ago

15

the distance between 2 station is 5400 m find the time taken by a train to cover this distance, if the train travels with speed

60m/s

2 answers:

iragen [17]2 years ago

8 0

Answer:

I dont know bro

Explanation:

Ask an expert

strojnjashka [21]2 years ago

5 0

Answer:

Time=90s

Explanation:

Speed=distance /time

$60 = \frac{5400}{t} where \: t \: is \: time \\60t = 5400 \\ t = \frac{5400}{60} \\ t =90 \\ hope \: this \: helps..good \: luck$

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series RC circuit is built with a 15 kΩ resistor and a parallel-plate capacitor with 18-cm-diameter electrodes. A 18 V, 36 kHz s

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Answer:

$d=1.84\ mm$

Explanation:

<u>Capacitance</u>

A two parallel-plate capacitor has a capacitance of

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Solving for C

$\displaystyle C=\frac{1}{wX_c}$

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$Z^2=R^2+X_c^2$

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$X_c^2=Z^2-R^2$

The magnitude of the impedance is computed as the ratio of the rms voltage and rms current

$\displaystyle Z=\frac{V}{I}$

The rms current is the peak current Ip divided by $\sqrt{2}$ , thus

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$I_p=0.65\ mA/1000=0.00065\ A$

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$\displaystyle X_c^2=Z^2-R^2=\left(\frac{\sqrt{2}V}{I_p}\right)^2-R^2$

Or, equivalently

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$X_c=36176.34\ \Omega$

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$\displaystyle C=\frac{1}{226194.67\cdot 36176.34}=1.22\cdot 10^{-10}\ F$

The radius of the plates is

$r=18\ cm/2=9 \ cm = 0.09 \ m$

The separation between the plates is

$\displaystyle d=\frac{8.85\cdot 10^{-12} \cdot \pi\cdot 0.09^2}{1.22\cdot 10^{-10}}$

$d=0.00184\ m$

$\boxed{d=1.84\ mm}$

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