The answer to this question is true.
Explanation:
Let's solve the problem by using conservation of momentum:
m1 u1 + m2 u2 = m1 v1 + m2 v2
where:
m1 = 3.5 g is the mass of the blue marble
m2= 1.2 g is the mass of the red marble
u1 = 15 cm/s is the initial velocity of the blue marble
u2 = 3.5 cm/s is the initial velocity of the red marble
v1 = 5.5 cm/s is the final velocity of the blue marble
We can find the final velocity of the red marble by re-arranging the equation and solving for v2 :
v2 = 1/m²(m1 u1 + m2 u2 - m1 v1)=
=1/1.2(3.5×15+1.2×3.5−3.5×5.5 )=31cm/s
Speed is not a vector so horizontal speed does not sighify anything. If u meant velocity it vill be same as the initial velocity in horizontal direction
Answer:
False.
Explanation:
Mass is how much space an object takes up, while weight is how light or heavy an object is.
The angle above the horizontal of the motion of mass A + B after the collision. as well as others are mathematically given as

- vf/vA= 0.94
- 2vf^2 / 5vA^2 = 0.35
<h3>What is
Collison equilibrium?</h3>
According to the collision hypothesis of chemistry, chemical reactions happen when two molecules or atoms collide.
Generally, the equation for Collison equilibrium is mathematically given as
For horizontal motion
mvAx+m2vAx = 2mvfx
For vertical motion
-mvAy+m2vAy = 2mvfy
vfy = 1/2 vAy


(b)

vf/vA= 0.94
(c)
![Ef/Ei = \frac{(1/2 * (2m) * (vf)^2) }{ (1/2 * m * (vA)^2) + 1/2*m*(2vA)^2) ]}](https://tex.z-dn.net/?f=Ef%2FEi%20%3D%20%5Cfrac%7B%281%2F2%20%2A%20%282m%29%20%2A%20%28vf%29%5E2%29%20%7D%7B%20%281%2F2%20%2A%20m%20%2A%20%28vA%29%5E2%29%20%2B%201%2F2%2Am%2A%282vA%29%5E2%29%20%5D%7D)
2vf^2 / 5vA^2 = 0.35
In conclusion, The angle above the horizontal of the motion of mass A + B after the collision. as well as others

vf/vA= 0.94
2vf^2 / 5vA^2 = 0.35
Read more about collision theory
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