It is practical research of Boyle’s law..
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<u>Answer:</u> The actual yield of the carbon dioxide is 47.48 grams
<u>Explanation:</u>
For the given balanced equation:
To calculate the mass for given number of moles, we use the equation:
Theoretical moles of carbon dioxide = 1.30 moles
Molar mass of carbon dioxide = 44 g/mol
Putting values in above equation, we get:
To calculate the theoretical yield of carbon dioxide, we use the equation:
Theoretical yield of carbon dioxide = 57.2 g
Percentage yield of carbon dioxide = 83.0 %
Putting values in above equation, we get:
Hence, the actual yield of the carbon dioxide is 47.48 grams
It is represented by C) KI
K+
I-
So it's KI
Answer:
C
Explanation:
they can be put in other languages
they are literally the name of the chemical
they don't show quantity
Answer:
H₂SO₄
Explanation:
We have a compound formed by 0.475 g H, 7.557 g S, 15.107 g O. In order to determine the empirical formula, we have to follow a series of steps.
Step 1: Calculate the total mass of the compound
Total mass = mass H + mass S + mass O = 0.475 g + 7.557 g + 15.107 g
Total mass = 23.139 g
Step 2: Determine the percent composition.
H: (0.475g/23.139g) × 100% = 2.05%
S: (7.557g/23.139g) × 100% = 32.66%
O: (15.107g/23.139g) × 100% = 65.29%
Step 3: Divide each percentage by the atomic mass of the element
H: 2.05/1.01 = 2.03
S: 32.66/32.07 = 1.018
O: 65.29/16.00 = 4.081
Step 4: Divide all the numbers by the smallest one
H: 2.03/1.018 ≈ 2
S: 1.018/1.018 = 1
O: 4.081/1.018 ≈ 4
The empirical formula of the compound is H₂SO₄.
