Answer:
135° and 225°
Step-by-step explanation:
basically you want to find the value of x between 0 and 360 in this equation
cos x/2 = -(√2)/2
assume x/2 as n, so
cos n = -(√2)/2
n = 45°
then remember the quadrant system
0-90 1st quadrant, all is POSITIVE
90-180 2nd quadrant, only SIN has positive value
180 - 270 3rd quadrant, only TAN has positive value
270 -360 4th quadrant, only COS positive here.
so if you try to find negative value look into 2nd and 3rd quadrant that related 45° to x-axis (0°or 180°)
so the value of x is
180 - 45 = 135° (2nd quadrant) and
180 + 45° = 225° (3rd quadrant)
The one above me is correct
Answer:
6x^2+5x-6
Step-by-step explanation: The only change you have to is add -3 and 8 which is 5 (Dont forget the x) and there you have it .
Use this equation y = a (1 - b)^x
Where a is the initial population and b is the decay factor: 40/100 = 0.4
Therefore, the answer is that the decay factor b is 0.4.
This table shows some figures using the decay factor.
year decrease population
0 0 a(1 - 0.4)^0 = a
1 a*0.4 a (1 - 0.4)^1 = a*0.6 = 0.6a
2 0.6a*0.4 a(1 - 0.4)^2 = a(0.6)^2 = 0.36a
3 0.36a*0.4 a(1 -0.4)^3= a(0.6)^3 = 0.216a
