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Serggg [28]
3 years ago
13

A study showed that the relationship between the number of years a person smokes and the cost of their health care during their

adult lifetime can be modeled by the equation
y = 4000x + 400,000, where x is the number of years smoking and y is the cost of health care in dollars.

Which of these statements is true according to the model?

Mathematics
2 answers:
Nataliya [291]3 years ago
4 0
Answer is 100% B

You should get it right
VLD [36.1K]3 years ago
3 0

Answer:

B

Step-by-step explanation:

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4/9 + 1/4 divided by 5/6
Hoochie [10]
Use order of operations (PENDAS)to divide 1/4 by 5/6 (remember to use the reciprocal of the second number). Than find GCF with that number you have now and 4/9 to get your answer.
6 0
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100th number in this sequence <br><br> 14 ,28 ,42 ,56
liraira [26]
It is 1,400 Since 14x100=1,400.
7 0
3 years ago
Select 2 options
madreJ [45]

Answer:

(×-5)(×+1)

×^2+×-5×-5

×^2-4×-5

8 0
3 years ago
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Will give brainlly
sdas [7]

Answer:

A

Step-by-step explanation:

With this question, its actually way easier than you think. If you want to find corresponding angles, you have to find a way to make the shapes overlap to be exactly the same. If they cannot be exactly the same, there will not be corresponding angles. For this, if you rotate quadrilateral 90 degrees counter-clockwise, you will see that the shapes look the same. Then you can just match up the angles that have the same degree measure (or just look the same for simplicity) and you have your answer. The answer is actually in the question too. ABCD=JKLM, but each letter is actually in the right place. A=J B=K C=L D=M.

Hope this helped! ^-^

7 0
3 years ago
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Prove that sin3a-cos3a/sina+cosa=2sin2a-1
Sloan [31]

Answer:

\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1

Step-by-step explanation:

we are given

\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1

we can simplify left side and make it equal to right side

we can use trig identity

sin(3a)=3sin(a)-4sin^3(a)

cos(3a)=4cos^3(a)-3cos(a)

now, we can plug values

\frac{(3sin(a)-4sin^3(a))-(4cos^3(a)-3cos(a))}{sin(a)+cos(a)}

now, we can simplify

\frac{3sin(a)-4sin^3(a)-4cos^3(a)+3cos(a)}{sin(a)+cos(a)}

\frac{3sin(a)+3cos(a)-4sin^3(a)-4cos^3(a)}{sin(a)+cos(a)}

\frac{3(sin(a)+cos(a))-4(sin^3(a)+cos^3(a))}{sin(a)+cos(a)}

now, we can factor it

\frac{3(sin(a)+cos(a))-4(sin(a)+cos(a))(sin^2(a)+cos^2(a)-sin(a)cos(a)}{sin(a)+cos(a)}

\frac{(sin(a)+cos(a))[3-4(sin^2(a)+cos^2(a)-sin(a)cos(a)]}{sin(a)+cos(a)}

we can use trig identity

sin^2(a)+cos^2(a)=1

\frac{(sin(a)+cos(a))[3-4(1-sin(a)cos(a)]}{sin(a)+cos(a)}

we can cancel terms

=3-4(1-sin(a)cos(a))

now, we can simplify it further

=3-4+4sin(a)cos(a))

=-1+4sin(a)cos(a))

=4sin(a)cos(a)-1

=2\times 2sin(a)cos(a)-1

now, we can use trig identity

2sin(a)cos(a)=sin(2a)

we can replace it

=2sin(2a)-1

so,

\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1


7 0
3 years ago
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