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yawa3891 [41]
4 years ago
12

What do the inner planets and outer planets have in common

Mathematics
1 answer:
Klio2033 [76]4 years ago
7 0
The Inner<span> and </span>Outer planets have<span> many things in </span>common, they both orbit around a star (In this case the star they orbit is the Sun) <span>All eight </span>planets<span> are round which make them similar.</span>
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Sergeeva-Olga [200]

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Step-by-step explanation:

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3 years ago
Jane has her height measured using a metric ruler as 1.6 meters. She would like to know her height in inches. She knows that the
slavikrds [6]

Answer:

Jane's height is <u>63 inches</u>.

Step-by-step explanation:

Given:

Jane has her height measured using a metric ruler as 1.6 meters. She would like to know her height in inches. She knows that there are 100 centimeters in a meter and 2.54 centimeters in an inch.

Now, to find jane's height to the nearest inch.

The height of Jane measured using metric ruler = 1.6 meters.

As, 1 meter = 100 centimeters.

So, by using conversion factor we convert the height of Jane into centimeters from meters:

1.6\ meter=1.6\times 100

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Now, we convert the centimeters by using unitary method:

If, 2.54 centimeters = 1 inch.

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3 years ago
If cos θ= 12 /13 and θ is located in the Quadrant I, find sin (2 θ ), cos(2 θ ), tan(2 θ )
Yakvenalex [24]

Answers: sin(2∅) = 120/169,  cos(2∅) = 119/169, tan(2∅) = 120/119

<h3>What are trigonometric functions?</h3>

Trigonometric functions are used to establish the relationship between the sides and the angles of a right angle triangle.

Analysis:

If cos∅ = adjacent/hypotenuse =  12/13,

Then, opposite of the right angled triangle = \sqrt{13^{2} - 12^{2}  } = 5

sin∅ = 5/13, cos∅ = 12/13, tan∅ = 5/12

sin(2∅) = 2sin∅cos∅ = 2(5/13)(12/13) = 120/169

cos(2∅) = cos^{2}∅ - sin^{2}∅ = (\frac{12}{13}) ^{2} - (\frac{5}{13} )^{2} = 144/169 - 25/169 = 119/169

tan(2∅) = sin(2∅) / cos(2∅)  = 120/169 ÷ 119/169 = 120/119

Learn more about trigonometric functions: brainly.com/question/24349828

#SPJ1

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2 years ago
In a group of 54 children, there are twice as many boys as girls how many girls are there
vlabodo [156]
2x + x = 54   wher x = number of girls

3x = 54 
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18 girls

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