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scoray [572]
3 years ago
11

Why is it important that an astronomer studies physics?

Physics
2 answers:
djyliett [7]3 years ago
8 0

Answer:

Astrophysicists study the physics of the universe. “Astrophysics” is a term that is often used interchangeably with “astronomy.” Atomic, molecular, and optical physicists study atoms, simple molecules, electrons, and light, as well as the interactions among them

Explanation:

Anvisha [2.4K]3 years ago
7 0
Physicists and astronomers conduct research to understand the nature of the universe and everything in it. These scientists observe, measure, interpret, and develop theories to explain celestial and physical phenomena using mathematics. From the vastness of space to the infinitesimal scale of subatomic particles, they study the fundamental properties of the natural world and apply the knowledge gained to design new technologies.
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A 5-kg ball collides inelastically head-on with a 10-kg ball, which is initially stationary. Which of the following statements i
Veseljchak [2.6K]

a. The magnitude of the change of the momentum of the 5-kg ball is equal to the magnitude of the change of momentum of the 10-kg ball.

c. The magnitude of the change of velocity the 5-kg ball experiences is greater than that of the 10-kg ball.

Explanation:

For an inelastic collision:

  • The total momentum of the system is conserved
  • The total kinetic energy of the system is not conserved

Using these facts, let's now analyze each statement given.

a. The magnitude of the change of the momentum of the 5-kg ball is equal to the magnitude of the change of momentum of the 10-kg ball.  --> TRUE. Since the total momentum is conserved, we can write:

p_1 = p_1'+p_2'

where

p_1 is the initial momentum of the 5-kg ball

p_1' is the final momentum of the 5-kg ball

p_2' is the final momentum of the 10-kg ball

The equation can be rewritten as

p_1-p_1'=p_2'

which is equivalent to

-\Delta p_1 = \Delta p_2

which means that the magnitude of the change of momentum of the two balls is the same.

b. Both balls lose all their momentum since the collision is inelastic.  --> FALSE, the 10-kg ball gains momentum, so it does not lose it.

c. The magnitude of the change of velocity the 5-kg ball experiences is greater than that of the 10-kg ball.  --> TRUE. We already said that the magnitude of the change in momentum of the two balls is the same. However, it can be written as

\Delta p = m\Delta v

where m is the mass of the ball and \Delta v its change in velocity. Therefore, the 5-kg ball (which has smaller mass) will have a larger \Delta v, so a larger change in velocity.

d. The magnitude of the change of velocity the 5-kg ball experiences is equal to that of the 10-kg ball.  --> FALSE, as we discussed in c).

e. The magnitude of the change of velocity the 5-kg ball experiences is less than that of the 10-kg ball. --> FALSE, as we discussed in c).

Learn more about change in momentum:

brainly.com/question/9484203

#LearnwithBrainly

6 0
4 years ago
a 25 newton force applied on an object moves it 50 meters. the angle between the force and displacement is 40.0°. what is the va
LiRa [457]
Work = force × distance × cos(angle)

work = (25)(50)(cos (40))

work = 957.56 Joules

= 9.6x10^2 Joules
3 0
3 years ago
A tool industry characterized by the appearance of hand axes, a bifacial type of blade.
marshall27 [118]
The stone tool industry being described is the Acheulean. These tools are characterized by hand axes and bifacial blades and were made by many different species of Homos, including Homo erectus and early Homo sapiens.
7 0
3 years ago
A 20-kg block slides down a fixed rough curved track The block has a speed of 5 0 m/s after its height above a horizontal surfac
Crank

Answer:

U = 102.8 J (100 J to two significant digits)

Explanation:

potential energy converted = 20(9.8)(1.8) = 352.8 J

kinetic energy at base of track = ½(20)5.0² = 250 J

energy (work) of friction 352.8 - 250 = 102.8 J

8 0
3 years ago
A 1.0-cm-diameter pipe widens to 2.0, then narrows to 0.5. Liquid flows through the first segment at a speed of 4.0. What is the
uysha [10]

Answer:

3.14 ×  10⁻⁴  m³  /s

Explanation:

The flow rate (Q) of a fluid is passing through different cross-sections remains of pipe always remains the same.

Q = Area x velocity

Given:

Diameters of 3 sections of the pipe are given as  

d1  =  1.0  cm,  d2  =  2.0  cm  and  d3  =  0.5  cm.

Speed in the first segment of the pipe is  

v1  =  4  m/s.

From the equation of continuity the flow rate through different cross-sections remains the same.

Flow  rate  =  Q  =  A1  v1  =  A2  v2  =  A3  v3.

Q = A1v1

   =π/4  d²1  v1  =  π/4  * 0.01² ×4.0 m³/s  =  3.14 ×  10⁻⁴  m³  /s

3 0
3 years ago
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