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2 years ago

Based on the chemical equation, use the drop-down menu to choose the coefficients that will balance the chemical

Physics

1 answer:

MaRussiya [10]2 years ago

8 0

The coefficients in order are 2, 1, 1

<h3>What is balanced chemical equation?</h3>

A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge is the same for both the reactants and the products.

In other words, the mass and the charge are balanced on both sides of the reaction.

According to the given situation,

To balance the the chemical equation,

Step 1 - Add a 2 on the Na2HPO4:

2(Na₂HPO₄) ⇒ Na4P₂O₇ + H₂O

Step 2 -Next take count of each element on both sides to see if the 2 is balanced or not:

On the left there are 4 Na, 2 H, 2 P, and 8 O

On the right there are 4 Na, 2 H, 2 P, and 8 O

Step 3 - Now we will divide by 2

i.e. 2 NA.H. P

The coefficient of Na is 2 , Coefficient of H is 1 and Coefficient of P is 1

Therefore,

The coefficients in order are 2, 1, 1.

Learn more about balanced chemical equation here:

brainly.com/question/15052184

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See attachment below please.

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2 years ago

A block of mass 0.500 kg is pushed against a horizontal spring of negligible mass until the spring is compressed a distance x (F

Marrrta [24]

Answer:

Part a)

$x = 0.4 m$

Part b)

$v_i = 11.7 m/s$

Part c)

Speed is more than the required speed so it will reach the top

Explanation:

Part a)

As we know that there is no frictional force while block is moving on horizontal plane

so we can use energy conservation on the block

$\frac{1}{2}mv^2 = \frac{1}{2}kx^2$

$\frac{1}{2}0.500(12^2) = \frac{1}{2}(450)x^2$

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Part b)

If the track has average frictional force of 7 N then work done by friction while block slides up is given as

$W_f = -7( \pi R)$

$W_f = -7(\pi \times 1.00)$

$W_f = -22 J$

work done against gravity is given as

$W_g = - mg(2R)$

$W_g = -(0.500)(9.8)(2\times 1)$

$W_g = -9.8 J$

Now by work energy equation we have

$\frac{1}{2}mv_i^2 + W_f + W_g = \frac{1}{2}mv_f^2$

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Part c)

now minimum speed required at the top is such that the normal force must be zero

$mg = \frac{mv^2}{R}$

$v = \sqrt{Rg}$

$v = 3.13 m/s$

so here we got speed more than the required speed so it will reach the top

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3 years ago