The resistance of the cylindrical wire is
.
Here
is the resistance,
is the length of the wire and
is the area of
cross section. Since the wire is cylindrical
.
Comparing two wires,

Dividing the above 2 equations,

Since 
The above ratio is

We also have,

The current through the Silver wire will be 4.23 times the current through the original wire.
Answer:
Earth's atmosphere is a layer of gases surrounding the planet Earth and retained by the Earth's gravity. It contains roughly 78% nitrogen and 21% oxygen 0.97% argon and carbon dioxide 0.04% trace amounts of other gases, and water vapor. This mixture of gases is commonly known as air. Explanation:
We don't have enough information in the picture to answer that question.
The disembodied right hand could just as well grab the wire in the other direction, with the thumb pointing to the right.
Maybe if we knew WHY the hand is holding the wire in this direction, and what other electrical phenomenon may be involved, we might be able to say something about the current in the wire.
(Actually, we don't even know if it's a wire. It might be a soda straw, a coat hanger, or a pool cue.)
Answer:
v = 18.84 m/s
Explanation:
Let the question says,"The blade of a 0.30 m diameter fan rotates 1200 rev / min. calculate the tangential speed."
It is given that,
Diameter of a blade of fan is 0.3 m
Angular velocity of the fan is 1200 rev/min or 125.66 rad/s
We need to find the tangential speed of the fan. The relation is given by :

r is radius of fan

So, the tangential velocity is 18.84 m/s.
Answer:
3.528×10² V.
Explanation:
potential difference: This is the work done when one coulomb of charge moves from one point to another in an electric field. The S.I unit of potential difference is volt. The formula of potential difference is given as,
V = kq/r..................... Equation 1
And
E = kq/r² .................. Equation 2
Comparing equation 1 and equation 2,
V = E×r............................. Equation 3
Where V = potential difference, E = Electric field between the plate of the capacitor, r = distance between the plate.
Given: E = 6.3×10⁵ V/m, r = 0.56 mm = 0.00056 m.
Substitute into equation 3,
V = 6.3×10⁵×0.00056
V = 3.528×10² V.
Hence the potential difference of the plate = 3.528×10² V.