(a)The acceleration of the 1,400-kg boat will be 0.425 m/sec²
(b) If it starts from rest, the distance through which the boat moves in 20.0 s will be 85 m.
(c)Velocity at the end of that time will be 8.5 m/sec.
<h3>What is velocity?</h3>
The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
Given data;
Forwad force acting on the boat,v₁ = 1,800-N
Resistive force acting on the boat,v₂ = 1,200-N
The acceleration of the boat,a
Mass of boat,m = 1,400-kg
Initial velocity of boat,u= 0 m/sec
Distance travelled by boat,S = ?
Time for the boat travels,t = 20.0 s
Final velocity,V = ? m/sec
The net force on the boat;
F = F₁ - F₂
F = 1800 N - 1200 N
F = 600 N
From the defination of force;
F= ma
a = F / m
a = 600 N / 1400 kg
a = 0.425 m/sec²
b)
The distance through which the boat moves is 20.0 s;
![\rm x_f = x_ 0 + v_0 t + \frac{1}{2} at^2 \\\\ x_f = \frac{1}{2}at^2 \\\\ x_f = 0+0 + \frac{1}{2} at^2 \\\\ x_f = \frac{1}{2}\times 0.425 \times (20 )^ 2 \\\\ x_f = 85 \ m](https://tex.z-dn.net/?f=%5Crm%20x_f%20%3D%20x_%200%20%2B%20v_0%20t%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20at%5E2%20%5C%5C%5C%5C%20x_f%20%20%3D%20%5Cfrac%7B1%7D%7B2%7Dat%5E2%20%5C%5C%5C%5C%20x_f%20%3D%200%2B0%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20at%5E2%20%5C%5C%5C%5C%20x_f%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ctimes%200.425%20%5Ctimes%20%2820%20%29%5E%202%20%5C%5C%5C%5C%20x_f%20%20%3D%2085%20%5C%20m)
c)
The velocity at the end of that time is found as;
m/sec
Hence the acceleration of the boat, the distance through which the boat moves in 20.0 s, and velocity at the end of that time will be 0.425 m/sec²,85 m, and 8.5 m/sec.
To learn more about the velocity, refer to the link: brainly.com/question/862972
#SPJ1