Answer:
11.7 m
Explanation:
I assume north is the y direction and x is the east direction, so Δx refers to the displacement in the east direction.
First, find the time it takes for the velocity to change from directly north to directly east.
Given (in the y direction):
v₀ = 2.88 m/s
v = 0 m/s
a = 0.350 m/s² sin(-52.0°) = -0.276 m/s²
Find: t
v = at + v₀
(0 m/s) = (-0.276 m/s²) t + (2.88 m/s)
t = 10.4 s
Given (in the x direction):
v₀ = 0 m/s
a = 0.350 m/s² cos(-52.0°) = 0.215 m/s²
t = 10.4 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (0 m/s) (10.4 s) + ½ (0.215 m/s²) (10.4 s)²
Δx = 11.7 m
Answer:
kinetic energy (K.E) = 5.28 ×10⁻¹⁷
Explanation:
Given:
Mass of α particle (m) = 6.50 × 10⁻²⁷ kg
Charge of α particle (q) = 3.20 × 10⁻¹⁹ C
Potential difference ΔV = 165 V
Find:
kinetic energy (K.E)
Computation:
kinetic energy (K.E) = (ΔV)(q)
kinetic energy (K.E) = (165)(3.20×10⁻¹⁹)
kinetic energy (K.E) = 528 (10⁻¹⁹)
kinetic energy (K.E) = 5.28 ×10⁻¹⁷
Answer:
The speed of the bus is 40 km/hr so this means the bus is travelling at a speed of 40 km per hour.
Answer:
We have that Assuming No air resistance,the initial horizontal velocity of the cannonball is
From the question we are told that
A cannonball is shot from a cannon at a launch angle of 35 and an initial velocity of 147 m/s
Generally the equation for the horizontal velocity is mathematically given as
Therefore
Therefore Assuming No air resistance,the initial horizontal velocity of the cannonball is For more information on this visit
Explanation:
