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Bad White [126]
3 years ago
9

If a sprinter accelerates from rest to 12 m/s north , what is their change in velocity ?

Physics
2 answers:
Elden [556K]3 years ago
7 0
12 is the answer gjbxrhcdcvhbcbj
natima [27]3 years ago
5 0

Answer: It would be 12 m/s.

Explanation: It would be this because If you go from rest to sprint it would be 12 m/s. Also, I did this the other day.

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A sphere has a radius of 3.9cm and a density of 7.58 g/cm cubed. What is the mass?
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Answer:

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A uniform meter rule with a mass of 200g is suspended at zero mark pivotes at 22.0cm mark. calculate the mass of the rule.
denpristay [2]

Answer:

The mass of the rule is 56.41 g  

Explanation:

Given;

mass of the object suspended at zero mark, m₁ = 200 g

pivot of the uniform meter rule = 22 cm

Total length of meter rule = 100 cm

0                          22cm                                  100cm

-------------------------Δ------------------------------------

↓                                                                       ↓

200g                                                                 m₂  

Apply principle of moment

(200 g)(22 cm - 0)     = m₂(100 cm - 22 cm)

(200 g)(22 cm) = m₂(78 cm)

m₂ =  (200 g)(22 cm)  / (78 cm)

m₂ = 56.41 g  

Therefore,  the mass of the rule is 56.41 g                                            

3 0
3 years ago
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