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VikaD [51]
4 years ago
9

What is 1000J in Btu?

Engineering
2 answers:
Strike441 [17]4 years ago
6 0

1 BTU = 1055.06 joules **

(1000 J) x (1 BTU / 1055.06 J) = <em>0.9478 BTU</em>

<em></em>

** Note:  You'll have to accept my conversion factor, since I went and looked it up and you didn't.

dybincka [34]4 years ago
5 0

Answer:

0.948 Btu

Explanation:

1 Btu = 1055 J so \frac{1000}{1055} = 0.948 Btu

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The pattern in a simple____ truss is a zigzag
liberstina [14]

Answer:

Bridge

Explanation:

A common, simply bridge truss is the zigzag.

6 0
3 years ago
If y varies inversely as x, and y =14 when x=8 , find y when x=7
vodomira [7]

Answer:

16

Explanation:

8 0
3 years ago
A pipeline (NPS = 14 in; schedule = 80) has a length of 200 m. Water (15℃) is flowing at 0.16 m3/s. What is the pipe head loss f
dangina [55]

Answer:

Head loss is 1.64

Explanation:

Given data:

Length (L) = 200 m

Discharge (Q) = 0.16 m3/s

According to table of nominal pipe size , for schedule 80 , NPS 14,  pipe has diameter (D)= 12.5 in or 31.8 cm 0.318 m

We know, head\ loss  = \frac{f L V^2}{( 2 g D)}

where, f = Darcy friction factor

V = flow velocity

g = acceleration due to gravity

We know, flow rate Q = A x V

solving for V

V = \frac{Q}{A}

    = \frac{0.16}{\frac{\pi}{4} (0.318)^2} = 2.015 m/s

obtained Darcy friction factor  

calculate Reynold number (Re) ,

Re = \frac{\rho V D}{\mu}

where,\rho = density of water

\mu = Dynamic viscosity of water at 15 degree  C = 0.001 Ns/m2

so reynold number is

Re = \frac{1000\times 2.015\times 0.318}{0.001}

            = 6.4 x 10^5

For Schedule 80 PVC pipes , roughness (e) is  0.0015 mm

Relative roughness (e/D) = 0.0015 / 318 = 0.00005

from Moody diagram, for Re = 640000 and e/D = 0.00005 , Darcy friction factor , f = 0.0126

Therefore head loss is

HL = \frac{0.0126 (200)(2.015)^2}{( 2 \times 9.81 \times 0.318)}

HL = 1.64 m

7 0
4 years ago
A crystalline grain of aluminum in a metal plate is situated so that a tensile load is oriented along the [1 1 1] direction. Wha
Ivenika [448]

Answer: required tensile stress is 0.889 MPa

Explanation:

Given that;

tensile load is oriented along the [1 1 1] direction

shear stress is 0.242 MPa along [1 0 1] in the (1 1 -1) plane

first we determine

λ which is Angle between  [1 1 1]  and  [1 0 1]

so

cosλ = [ 1(1) +  1(0) + 1(1) ] / [ √(1² + 1² + 1²) √(1² + 0² + 1²)]

= 2 / √3√2 =  2/√6

Next, we determine ∅ which is angle between [1 1 1]  and  [1 1 -1]

so,

cos∅ = [ 1(1) +  1(1) + 1(-1) ] / [ √(1² + 1² + 1²) √(1² + 1² + (-1)²)]

cos∅ = [ 2-1] / [√3√3 ]

cos∅ = 1/3

Now, we know that;

σ = T_stress/cosλcosθ

so we substitute

σ = 0.242 / ( 2/√6 × 1/3 )

σ = 0.242 / 0.2721

σ = 0.889 MPa

Therefore, required tensile stress is 0.889 MPa

3 0
3 years ago
The form of mechanical weathering that occurs when a magma chamber starts expanding after the overlying volcano has been removed
Alexeev081 [22]

Answer:

Exfoliation.

Explanation:

Exfoliation is a form of chemical weathering that occurs when sheets of rocks peel from a massive rock's surface. It is also the unloading and sheeting of stress in a rock that expands the magma chamber.

5 0
3 years ago
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