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3 years ago

A baseball player runs 27.4 meters from the

Physics

2 answers:

swat323 years ago

8 0

Answer:

Option (3) 3.0 m longer

Explanation:

This is a question of displacement here. Let's look at the problem again and analyse.

The first distance run by the base = 3 m

The second distance to the base = 3 m

The total distance run = 6 m

The first base lags by 3 m, so the distance = 6 - 3

= 3 m.

sleet_krkn [62]3 years ago

6 0

6.0 m longer because the player ran 3 and came back 3 at the very end, which looks like he went nowhere but in reality he ran 6.

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A wave pulse travels down a slinky. The mass of the slinky is m = 0.87 kg and is initially stretched to a length L = 6.8 m. The

Ber [7]

Answer:

1. $v=14.2259\ m.s^{-1}$

2. $F_T=25.8924\ N$

3. $\lambda=29.6373\ m$

Explanation:

Given:

mass of slinky, $m=0.87\ kg$

length of slinky, $L=6.8\ m$

amplitude of wave pulse, $A=0.23\ m$

time taken by the wave pulse to travel down the length, $t=0.478\ s$

frequency of wave pulse, $f=0.48\ Hz=0.48\ s^{-1}$

$\rm Speed\ of\ wave\ pulse=Length\ of\ slinky\div time\ taken\ by\ the\ wave\ to\ travel$

$v=\frac{6.8}{0.478}$

$v=14.2259\ m.s^{-1}$

Now, we find the linear mass density of the slinky.

$\mu=\frac{m}{L}$

$\mu=\frac{0.87}{6.8}\ kg.m^{-1}$

We have the relation involving the tension force as:

$v=\sqrt{\frac{F_T}{\mu} }$

$14.2259=\sqrt{\frac{F_T}{\frac{0.87}{6.8}} }$

$202.3774=F_T\times \frac{6.8}{0.87}$

$F_T=25.8924\ N$

We have the relation for wavelength as:

$\lambda=\frac{v}{f}$

$\lambda=\frac{14.2259}{0.48}$

$\lambda=29.6373\ m$

8 0

3 years ago

A particular form of electromagnetic radiation has a frequency of 5.42x10^15 Hz. What is the wavelength is nanometers? meters?

zubka84 [21]

Electromagnetic radiation are represented in waves. Each type of wave has a certain shape and length. The distance between two peaks in a wave is called the wavelength. This value is equal to the speed of light divided by the frequency.
Wavelength = c/f
Wavelength = 3x10^8 / 5.42x10^15
Wavelength = 5.54 x 10^-8 m = 55.35 nm

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3 years ago

A zebra starts from rest and accelerates at 1.9 m/s how far has a zebra gone in five seconds

Maksim231197 [3]

To that multiply 1.9 by 5 to get 9.5. The zebra has gone 9.5 m.

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Marlon is studying a crab population. He has a large batch of crabs that were captured in the ocean. He places a plastic tag on

tatiyna

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Use the concept of fields to describe how forces can act from a distance.

Leni [432]

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