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neonofarm [45]
3 years ago
6

You are performing a double slit experiment very similar to the one from DL by shining a laser on two nattow slits spaced 7.5 x

103 meters apart. However, by placing a piece of crystal in one of the slits, you are able to make it so that the rays of light that travel through the two slits are Ï out of phase with each other (that is to say, Ao,- ). If you observe that on a screen placed 4 meters from the two slits that the distance between the bright spot clos center of the pattern is 1.5 cm, what is the wavelength of the laser?
Physics
1 answer:
Blizzard [7]3 years ago
7 0

Complete Question

You are performing a double slit experiment very similar to the one from DL by shining a laser on two nattow slits spaced 7.5 * 10^{-3} meters apart. However, by placing a piece of crystal in one of the slits, you are able to make it so that the rays of light that travel through the two slits are Ï out of phase with each other (that is to say, Ao,- ). If you observe that on a screen placed 4 meters from the two slits that the distance between the bright spot closest to center of the pattern is 1.5 cm, what is the wavelength of the laser?

Answer:

The  wavelength is  \lambda  =  56250 nm

Explanation:

From the question we are told that

   The  distance of slit separation is  d =  7.5 *10^{-3} \  m

   The  distance of the screen is  D =  4 \  m

    The  distance between the bright spot closest to the center of the interference  is  k   = 1.5 \ cm = 0.015 \  m

   

Generally the width of the central  maximum fringe produced is mathematically represented as

        y  =  2 *  k  = \frac{ D  *  \lambda}{d}

  =>    2 *  0.015 =  \frac{ \lambda  *  4}{ 7.5 *10^{-3}}

   =>   \lambda  =  56250 *10^{-9} \ m

=>      \lambda  =  56250 nm

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Explanation:

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The total acceleration of the projectile is given by the resultant of the horizontal and vertical components of the acceleration. But we said that the horizontal component is zero, therefore the total acceleration corresponds just to its vertical component, therefore it is a vector with magnitude 9.8 m/s^2 which points downward.

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