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malfutka [58]
4 years ago
10

Why are graphs helpful for displaying data?

Physics
2 answers:
Fed [463]4 years ago
8 0

Answer:

They help you see trends in the data.

3241004551 [841]4 years ago
6 0
C is the answer i think
You might be interested in
Steam flows steadily through an adiabatic turbine. The inlet conditions of the steam are 4 MPa, 500◦C, and 80 m/s, and the exit
Cerrena [4.2K]

Answer:

a) ΔEC=-23.4kW

b)W=12106.2kW

c)A=0.01297m^2

Explanation:

A)

The kinetic energy is defined as:

\frac{m*vel^2}{2} (vel is the velocity, to differentiate with v, specific volume).

The kinetic energy change will be: Δ (\frac{mvel^2}{2})=\frac{m*vel_2^2}{2}-\frac{m*vel_1^2}{2}

Δ (\frac{mvel^2}{2})=\frac{m}{2}*(vel_2^2-vel_1^2)

Where 1 and 2 subscripts mean initial and final state respectively.

Δ(\frac{mvel^2}{2})=\frac{12\frac{kg}{s}}{2}*(50^2-80^2)\frac{m^2}{s^2}=-23400W=-23.4kW

This amount is negative because the steam is losing that energy.

B)

Consider the energy balance, with a neglective height difference: The energy that enters to the turbine (which is in the steam) is the same that goes out (which is in the steam and in the work done).

H_1+\frac{m*vel_1^2}{2}=H_2+\frac{m*vel_2^2}{2}+W\\W=m*(h_1-h_2)+\frac{m}{2} *(vel_1^2-vel_2^2)

We already know the last quantity: \frac{m}{2} *(vel_1^2-vel_2^2)=-Δ (\frac{mvel^2}{2})=23400W

For the steam enthalpies, review the steam tables (I attach the ones that I used); according to that, h_1=h(T=500C,P=4MPa)=3445.3\frac{kJ}{kg}

The exit state is a liquid-vapor mixture, so its enthalpy is:

h_2=h_f+xh_{fg}=289.23+0.92*2366.1=2483.4\frac{kJ}{kg}

Finally, the work can be obtained:

W=12\frac{kg}{s}*(3445.3-2438.4)\frac{kJ}{kg} +23.400kW)=12106.2kW

C) For the area, consider the equation of mass flow:

m=p*vel*A where p is the density, and A the area. The density is the inverse of the specific volume, so m=\frac{vel*A}{v}

The specific volume of the inlet steam can be read also from the steam tables, and its value is: 0.08643\frac{m^3}{kg}, so:

A=\frac{m*v}{vel}=\frac{12\frac{kg}{s}*0.08643\frac{m^3}{kg}}{80\frac{m}{s}}=0.01297m^2

Download pdf
7 0
4 years ago
The electric current in a wire is 1.5A. How many electrons flow past a given point in a time of 2s?
kipiarov [429]

Answer:

The amount of electrons that flow in the given time is 3.0 C.

Explanation:

An electric current is defined as the ratio of the quantity of charge flowing through a conductor to the time taken.

i.e           I = \frac{Q}{t} ...................(1)

It is measure in Amperes and can be measured in the laboratory by the use of an ammeter.

In the given question, I = 1.5A, t = 2s, find Q.

From equation 1,

            Q = I × t

                = 1.5 × 2

               = 3.0 Coulombs

The amount of electrons that flow in the given time is 3.0 C.

5 0
3 years ago
What is word meaning "heated to a glow"?
adell [148]

I think the word you want is "incandescent".


5 0
3 years ago
describe the physics modeling process in moving a basketball and say what effects you should overlook​
Dahasolnce [82]

Answer:ui9i

Explanation:

jiooooooooooooo

7 0
3 years ago
URGENT!! ILL GIVE BRAINLIEST! AND 100 POINTS
lubasha [3.4K]

The inertia with the speed of 2.9 m/s has moved a distance of 3.6 kilometers in the west direction and 2.35 kilometers in the north direction.

<h3>What are trigonometric ratio?</h3>

In mathematics, the trigonometric functions are real functions which relate an angle of a right-angled triangle to ratios of two side lengths. They are widely used in all sciences that are related to geometry, such as navigation, solid mechanics, celestial mechanics, geodesy, and many others.

Given:

Speed of the speed 2.9 m/s

The direction in which the inertia change is moving = 43° north west.

Time taken to travel the distance = 30 minutes

According to the question that is moving in a Northwest direction with a velocity of 2.9 m per second.

If you want to find the distance it has moved in either North or west direction you will first have to find the total distance that kayak has moved in 30 minutes.

The distance travel by the kayak in 30 minutes = speed of person × time taken

The distance travel by the person in 30 minutes = 2.9 × 30 × 60

The distance travel by the person in 30 minutes = 5220 metre

The distance travel by the person in 30 minutes = 5.22 km

The distance traveled in the west direction can be find using trigonometric ratio.

5.2 × sin 43 = The distance traveled in the west direction

The distance traveled in the west direction = 3.6 kilometers

The distance traveled in the west = cos 43 × 5.2

The distance traveled in the west = 2.35 km

Therefore, The person with the speed of 2.9 m/s has moved a distance of 3.6 kilometers in the west direction and 2.35 kilometers in the north direction.

Learn more about the trigonometric ratio here:

brainly.com/question/26719838

#SPJ9

6 0
2 years ago
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