Given:
rod of circular cross section is subjected to uniaxial tension.
Length, L=1500 mm
radius, r = 10 mm
E=2*10^5 N/mm^2
Force, F=20 kN = 20,000 N
[note: newton (unit) in abbreviation is written in upper case, as in N ]
From given above, area of cross section = π r^2 = 100 π =314 mm^2
(i) Stress,
σ
=force/area
= 20000 N / 314 mm^2
= 6366.2 N/mm^2
= 6370 N/mm^2 (to 3 significant figures)
(ii) Strain
ε
= ratio of extension / original length
= σ / E
= 6366.2 /(2*10^5)
= 0.03183
= 0.0318 (to three significant figures)
(iii) elongation
= ε * L
= 0.03183*1500 mm
= 47.746 mm
= 47.7 mm (to three significant figures)
<span>The Solar electricity source of
energy comes from the sun’s rays. It is more often in the form of a panel known
as the solar panel. It has a photovoltaic system that generates and supplies
energy in commercial and residential areas. Even though numerous countries are
using this type of electricity to save electric-induced power, it is not used
for a number of reasons. One is that 1 panel with a size of 6 by 10 solar cells
is expensive. There are countries who cannot afford to buy them. Two, it
requires a larger area to place the panel. Three, the efficiency is low. The smaller
the panel is, the lower its efficiency and therefore produces lesser power to
generate a specific area. </span>
Kepler's third law is used to determine the relationship between the orbital period of a planet and the radius of the planet.
The distance of the earth from the sun is 
.
<h3>
What is Kepler's third law?</h3>
Kepler's Third Law states that the square of the orbital period of a planet is directly proportional to the cube of the radius of their orbits. It means that the period for a planet to orbit the Sun increases rapidly with the radius of its orbit.
Given that Mars’s orbital period T is 687 days, and Mars’s distance from the Sun R is 2.279 × 10^11 m.
By using Kepler's third law, this can be written as,
Substituting the values, we get the value of constant k for mars.
The value of constant k is the same for Earth as well, also we know that the orbital period for Earth is 365 days. So the R is calculated as given below.
Hence we can conclude that the distance of the earth from the sun is .
To know more about Kepler's third law, follow the link given below.
brainly.com/question/7783290.
As we know that centripetal acceleration is given as
here we know that
linear speed = 35 m/s
here radius of path is same as length of arm
R = 0.7 m
now from above above formula we have
so acceleration is 1750 m/s/s
Answer:
the rocks are away from cracks in the crust
Explanation:
The new crust is pushed away from the Ocean Ridge in both directions as newer crust is formed. This is called sea floor spreading. The crust that makes up the sea floor starts to have time to accumulate a layer of sediments as it gets older and moves away from the Ocean Ridge.
