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NARA [144]
3 years ago
9

if the same amount of work needed to keep a 100W light bulb lit for one hour could be used to lift a 2000 kg SUV, what height co

uld it be lifted to?
Physics
1 answer:
yulyashka [42]3 years ago
5 0

(100 watts) = 100 joules/second

(100 joules/second) x (3,600sec/hour) = 360,000 joules/hour

360,000 joules = 360,000 newton-meters

Weight of 2,000 kg on Earth = (2,000 kg) x (9.8 m/s²) = 19,600 newtons

(360,000 newton-meters) / (19,600 newtons) = <em>18.4 meters off the ground</em>


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A boat is drifting with a speed of 5.0\,\dfrac{\text m}{\text s}5.0 s m ​ 5, point, 0, space, start fraction, m, divided by, s,
zepelin [54]

Answer:

d=42m(-\hat{i})

Explanation:

For this problem, we need to apply the formulas of constant accelerated motion.

To obtain the boat displacement we need to calculate the displacement because of the river flow and the displacement done because of the boat motor.

for the river:

d_r=v*t\\d_r=5m/s*6s\\d_r=30m(\hat{i})

for the boat:

x=\frac{1}{2}*a*t^2\\\\x=\frac{1}{2}*4.0m/s*(6s)^2\\\\\\x=72m(-\hat{i})

So the final displacement is given by:

d=dr+x\\d=30m-72m\\d=42m(-\hat{i})

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3 years ago
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What is the correct explanation of Newton's Third Law of Motion?
viva [34]

Answer:

a

Explanation:

it explains the most, and it is the correct theorem

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Explain three differences between a science and a pseudoscience.
grin007 [14]
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3 years ago
The Millennium Falcon was constructed 43.6 m long. a) How fast is it traveling past Luke when he measures its length to be 30.1
Zinaida [17]

Answer:

a)0.5564c

b)43.6 m

Explanation:

Given proper length of falcrum L₀= 43.6 m

improper length L=30.1 m (when viewed from moving frame)

we know that L=L_{0}\sqrt{1-\frac{v^2}{c^2}}

30.1=43.6\sqrt{1-\frac{v^2}{c^2}

⇒\{1-\frac{v^2}{c^2}}=\frac{30.1}{43.6}

{1-\frac{v^2}{c^2}}=0.6904

\frac{v^2}{c^2}=0.3096

v^{2}=3096c^{2}

v=0.5564c

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8 0
3 years ago
When a flat slab of transparent material is placed under water, the critical angle for light traveling from the slab into water
Novosadov [1.4K]

Answer:

(a) 40.6 degree

Explanation:

When refraction takes place from slab to water, the critical angle is 60 degree.

Use Snell's law

refractive index of water with respect to slab

\mu _{w}^{s}=\frac{Sin60}{Sin90}

\frac{\mu _{w}}{\mu _{s}}=0.866

\frac{1.33}{\mu _{s}}=0.866

μs = 1.536

Now for slab air interface, the critical angle is C.

\mu _{a}^{s}=\frac{SinC}{Sin90}

\frac{\mu _{a}}{\mu _{s}}=\frac{SinC}{Sin90}

1 / 1.536 = Sin C

C = 40.6 degree

3 0
3 years ago
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