Answer:
chromoblastomycosis
Explanation:
Here is the complete question;. A sample of the tissue from an inflamed, pus-filled area on the lower leg is treated with KOH and stained with GMS. Under the microscope golden brown spheres are visible. What disease are these observations consistent with?
A) pityriasis
B) fungemia
C) chromoblastomycosis
D) mycetoma
E) sporotrichosis
Answer is
C) chromoblastomycosis
Chromoblastomycosis is a chronic fungal infection of the skin and the subcutaneous tissue caused by traumatic inoculation of a specific group of dematiaceous fungi (usually Fonsecaea pedrosoi, Phialophora verrucosa, Cladosporium carrionii, or Fonsecaea compacta) through the skin.
If the dominant allele is t and the recessive allele ("non-taster") is n, than tn and tt are the genotypes of a "taster". tn is heterozygous and tt is dominant homozygous. nn is the genotype of a "non-taster" and it is recessive homozygous.
First calculate the probability of type AB, which is the remainder after subtracting types A, B and O.
P(AB) = 1-(0.34+0.12+0.5) = 1-0.96 = 0.04
Anti-b will react with types B and AB, so
P(reaction) = P(B)+P(AB) = 0.12 + 0.04 = 0.16
Answer: For this person, the probability of reaction with anti-b is 0.16
Your answer will be B plants makes their own food. They also have a cell wall and animals don't.
