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ElenaW [278]
3 years ago
12

Calculate the amount of CO2 produced when 1.00 mole of propane (C3H8) is burned in the presence of 1.00 mole of oxygen.

Chemistry
1 answer:
Anna [14]3 years ago
4 0

<u>Answer:</u>

The balanced Chemical equation is

1C_3 H_8  +5O_2  >3CO_2+4H_2 O

Since quantity of two reactants are given Hence we find the moles of product using both.

The quantity of product produced is the one we consider from the limiting reactant.

Limiting reactant is the reactant which runs out first.

So, least product is produced from the limiting reactant.

Mole ratio of C_3 H_8:CO_2 is 1: 3

$1.00 \mathrm{mol} \mathrm{C}_{3} \mathrm{H}_{\mathrm{8}} \times \frac{3 \mathrm{mol} \mathrm{CO}_{2}}{1 \mathrm{mol} \mathrm{C}_{3} \mathrm{H}_{8}}=3 \mathrm{molCO}_{2}$

Mole ratio of O_2:CO_2 is 5: 3

$1.00 \mathrm{mol} \mathrm{O}_{2} \times \frac{3 \mathrm{mol} \mathrm{co}_{2}}{5 \mathrm{mol} \mathrm{O}_{2}}=0.6 \mathrm{mol} \mathrm{CO}_{2}$

(Least produced)

So, the limiting reactant is O_2

The amount of CO_2 formed is 0.600mol (Answer)

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Answer:

Pure elements:

Hydrogen(H)

Nitrogen(N)

Magnesium (Mg)

Pure Compounds:

Oxygen gas(O2)  

Water (H2O)  

Ammonia (NH3)

Explanation:

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At what point is base no longer added during a titration
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AVprozaik [17]

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3 0
3 years ago
1. Draw a wedge/dash structure for trans-1,2-dimethylcyclohexane.
Angelina_Jolie [31]

Answer:

The structure with the ring flipped is the most stable

Explanation:

We have the  trans 1,2 - dimethylcyclohexane. With the wedge/dash structure we could not figure is this form is stable (If we do a comparison with the cis structure). But when we do a chair structure and ring flipped structure, this is easier to look.

The picture attached shows the structures, they are labeled as 1, 2 and 3, according to this problem.

In the chair structure, according to the picture below, you can see that both methyls are heading in the axial positions of the ring (One facing upward and the other downward). This is pretty stable, however, when the methyls are in those positions, the methyl position 1, can undergoes an 1,3 diaxial interactions with the hydrogens atoms (They are not drawn, but still are there), so this interaction makes this structure a little less stable that it can be.

On the other side, the ring flipped structure, we can see that both methyls are in the equatorials positions of the ring, and in these positions, it can avoid the 1,4 diaxial interactions with the hydrogens atoms, making this structure the most stable structure.

Hope this helps

6 0
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