From the equation q=mCΔT, set the q of copper = to q of water,
So --- mCΔT(copper)=mCΔT(water).
mass (Cu - copper) = 38g
mass (H2O - water) = 15g
C (H2O) = 4.184 J/g*C
ΔΤ (H2O) = 33-22 = 11*C
ΔΤ (Cu) = 33-80 = -47*C (the final temp is the same for both materials - thermal equilibrium)
C (Cu) = ?
So --- 38(-47)C[Cu]=15(4.184)(11)
--- C[Cu]=690.36/(-1786) = 0.3865 J/g*C, or 0.39 in 2 sig figs. (The negative goes away, because specific heats are usually positive)
Hydrogen, Helium
Hope this helps!
Answer:
See the answer below
Explanation:
The statement that could best explain how the offspring could inherit a trait not shown in the phenotypes of either parent would be that <u>both parents are heterozygous for the red color. </u>
Heterozygous parents can produce offspring with a phenotype that is distinctly different from that of either parent if the recessive alleles come together during random fusion of gametes.
Let us assume that the red color (R) in the New Hampshire chicken is the dominant one and the recessive one is the golden color (r). The genotype of the heterozygous parents would be Rr.
Rr x Rr
RR Rr Rr rr
<em>There is a probability (1/4) of producing a golden color chicken (rr), a trait that is not displayed in either of the parents.</em>
<span><span>4.2×1022</span>NA</span><span> N_{A} is the avagadro number</span>
Answer:
The answer to your question is: letter D.
Explanation:
Noble gases are located in group VIIIA of the periodic table, this means that they have 8 eight electrons in their outermost shell.
Due to this characteristic, they are stable and do not react with other elements.
a. 1s22s22p4 The outermost shell of this electron configuration has 6 electrons, then this element has 6 electrons not 8. This configuration is of an element of the group VIA.
b. [Ne]2s22p2 The outermost shell of this element has 4 electrons, so this is not the configuration of a noble gas.
c. [Ar] 3s1 This element only has one electron in its outermost shell, so this is the electron configuration of an alkaline metal.
d. 1s22s22p6 This element has 8 electrons in its outermost shell, so this is the electron configuration of a noble gas.