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Ksju [112]
3 years ago
5

Which factor would be most useful predicting the amount of mantle a certain volume of crust will displace

Chemistry
1 answer:
vovangra [49]3 years ago
8 0
Answer:
density of the crust

Explanation:
The displacement of the mantle by the continental or the ocean crust depends on a condition known as <span>isostasy which describes the gravitational equilibrium between both the mantle and the crust of the Earth.
If </span><span>isostasy is not preserved, this would mean that the equilibrium between the crust and the mantle is not maintained and that the crust would displace a volume of mantle.
The amount of mantle to be displaced usually depends on the density of the crust.

Hope this helps :)</span>
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Draw the structure of the major nitration product from the reaction of nitric acid with 1,3‑dimethylbenzene. Show all formal cha
solong [7]

The 2,4 and 5 positions are accessible for nitration of 1,3‑dimethylbenzene. The final product is shown in the image attached.

<h3>What is nitration?</h3>

Nitration is a type of reaction in which the nitro group (-NO2) is introduced to an aromatic ring. We have to note that in the compound 1,3‑dimethylbenzene, the 2,4 and 5 positions are accessible for nitration as shown.

Hence, the nitration of 1,3‑dimethylbenzene occurs  as shown in the image attached with the compound shown being the major product.

Learn more about nitration: brainly.com/question/5346392

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2 years ago
What is berylliums energy levels
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3 years ago
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6 0
3 years ago
2. A quantity of 1.922g of methanol (CH3OH) was burned in a constant-volume
Cerrena [4.2K]
Mass of methanol (CH3OH) = 1.922 g
Change in Temperature (t) = 4.20°C
Heat capacity of the bomb plus water = 10.4 KJ/oC
The heat absorbed by the bomb and water is equal to the product of the heat capacity and the temperature change.
Let’s assume that no heat is lost to the surroundings. First, let’s calculate the heat changes in the calorimeter. This is calculated using the formula shown below:
qcal = Ccalt
Where, qcal = heat of reaction
Ccal = heat capacity of calorimeter
t = change in temperature of the sample
Now, let’s calculate qcal:
qcal = (10.4 kJ/°C)(4.20°C)
= 43.68 kJ
Always qsys = qcal + qrxn = 0,
qrxn = -43.68 kJ
The heat change of the reaction is - 43.68 kJ which is the heat released by the combustion of 1.922 g of CH3OH. Therefore, the conversion factor is:
5 0
3 years ago
What is the molar mass of CaCl2?
alekssr [168]
Molar mass of CaCl2 = 40+ ( 35.5 ×2)=110

Mr of Ca(OH)2 = 40+ (16+1)×2 =74

%of Ca = (40÷ 74)×10=...

1 m = 100cm...
1cm = (1÷100) m
So 45.5 cm = 45.5 ×(1÷100) =....

1km = 1000m
1m = 100 cm
1cm =10mm
So 1km = 1000×100×10 mm
Now convert
7 0
3 years ago
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