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4 years ago

13

Which property justifies the fact that 5(x-2) is equivalent to 5x-10

2 answers:

irina1246 [14]4 years ago

7 0

The property that justifies this equivalence is the distributive property. you disribute by multiplying 5 and x to get 5x and 5 times negative 2 to get negative 10

Mazyrski [523]4 years ago

4 0

Hey there! :D

The distributive property is what makes 5(x-2) to 5x-10

The distributive property states that a(b+c)= ab+ac

So, 5(x-2)= 5x-10

I hope this helps!
~kaikers

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Does anyone know this?

barxatty [35]

Answer:

$\Huge \boxed{-2}$

Step-by-step explanation:

$f(x)=-2x^2-2x+10$

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$f(2)=-2(2)^2-2(2)+10$

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$f(2)=-2(4)-2(2)+10$

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Alex787 [66]

Answer:

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3 years ago

A student has some $1 and $5 bills in his wallet. he has a total of 15 bills that are worth $51. How much of each type of bill d

snow_tiger [21]

Answer:

# of 5 dollar bills: 9

# of 1 dollar bills: 6

Step-by-step explanation:

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3 years ago

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Elza [17]

Answer:

$(b)\ 2x - 9 = -1$

$(c)\ -2x + 12 = 4$

$(e)\ 2(x - 10) = -12$

Step-by-step explanation:

Required

Which equals $x = 4$

$(a)\ 2x + 6 = 2$

Collect like terms

$2x = 2 - 6$

$2x = -4$

Divide both sides by 2

$x = -2$

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Collect like terms

$2x = -1 + 9$

$2x = 8$

Divide both sides by 2

$x = 4$

$(c)\ -2x + 12 = 4$

Collect like terms

$-2x =- 12 + 4$

$-2x =-8$

Divide both sides by -2

$x = 4$

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$x + 2 =5$

Collect like terms

$x = 5-2$

$x = 3$

$(e)\ 2(x - 10) = -12$

Divide both sides by 2

$x - 10 = -6$

Collect like terms

$x = 10 - 6$

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Hence, the equations with the required solution are:

$(b)\ 2x - 9 = -1$

$(c)\ -2x + 12 = 4$

$(e)\ 2(x - 10) = -12$

3 0

3 years ago

Three cards are drawn from a standard deck of 52 cards without replacement. Find the probability that the first card is an ace,

MrRissso [65]

Answer:

$4.82\cdot 10^{-4}$

Step-by-step explanation:

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a = 4 (aces)

t = 4 (three)

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n = 52

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$p(a)=\frac{a}{n}=\frac{4}{52}=\frac{1}{13}=0.0769$

At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is

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Therefore, the probability of drawing a three at the 2nd draw is

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Then, at the third draw, the previous 2 cards are not replaced, so there are now

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$p(j)=\frac{j}{n-2}=\frac{4}{50}=0.08$

Therefore, the total probability of drawing an ace, a three and then a jack is:

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3 years ago