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lukranit [14]
3 years ago
13

A researcher reports survey results by stating that the standard error of the mean is 20. The population standard deviation is 5

00.
a. How large was the sample used in this survey?
b. What is the probability that the point estimate was within ±25 of the population mean?
Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
5 0

multiply 20 by 500. it should help you with the problem.

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Point A is at (-1, -9) and point M is at (0.5, -2.5).
vladimir2022 [97]

Answer:

Point B is located at point (2, 4)

Step-by-step explanation:

Since point M is at the center, you find the distance from point A and add that to the other side.

| -1 - 0.5 | = | -1.5 | = 1.5

| -9 - -2.5 | = | -6.5 | = 6.5

Now we can add that to point M to find point B

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A bag had 7 orange rocks , 6 green rock , 1 white rock ,7 black rocks , and 2 yellow you randomly pull a rock from the bag ,keep
daser333 [38]

Answer:

Probability = \frac{7}{253}

Step-by-step explanation:

Given

Orange = 7

Green = 6

White = 1

Black = 7

Yellow = 2

Required

Probability of selecting a yellow then orange rock

From the question, we understand that the probability is that of without replacement.

Since the yellow, is first picked.

We need to determine the probability of picking a yellow rock, first.

P(Yellow) = \frac{n(Yellow)}{Total}

P(Yellow) = \frac{2}{7 + 6 + 1 + 7 + 2}

P(Yellow) = \frac{2}{23}

The rock has reduced by 1;

Next is to determine the probability of picking an orange rock

P(Orange) = \frac{n(Orange)}{Total - 1}

P(Orange) = \frac{7}{7 + 6 + 1 + 7 + 2- 1}

P(Orange) = \frac{7}{22}

The required probability is calculated as thus:

Probability = P(Yellow) * P(Orange)

Probability = \frac{2}{23} * \frac{7}{22}

Probability = \frac{14}{506}

Probability = \frac{7}{253}

4 0
3 years ago
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